Answer:
The value is
Explanation:
From the question we are told that
The mass of matter converted to energy on first test is
The mass of matter converted to energy on second test
Generally the amount of energy that was released by the explosion is mathematically represented as
=>
=>
Answer:
Explanation:
See the file attached .
b ) Range of projectile
= u²sin2θ / g
= 42² sin32 x 2 / g
= 42² sin64 / 9.8
= 161.8 m
c )
Max height = u² sin²32 / 2 g
= 42² sin²32 / 2x 9.8
= 25.27 m .
The momentum of a neutron p = 586.25 kg m / s.
<u>Explanation:</u>
The product of mass and the velocity gives the momentum of an object and it is a vector quantity. It is denoted by the letter p. The unit of momentum is kilogram meter per second (or) kg m / s.
Given mass m = 1.675 10, velocity v = 3.500
10
Momentum, p = mv
where m represents the mass,
v represents the velocity.
momentum p = (1.675 10)
(3.500
10)
momentum p = 586.25 kg m / s.
Answer:
Explanation:
We apply Newton's second law at the crate :
∑F = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Data:
m=90kg : crate mass
F= 282 N
μk =0.351 :coefficient of kinetic friction
g = 9.8 m/s² : acceleration due to gravity
Crate weight (W)
W= m*g
W= 90kg*9.8 m/s²
W= 882 N
Friction force : Ff
Ff= μk*N Formula (2)
μk: coefficient of kinetic friction
N : Normal force (N)
Problem development
We apply the formula (1)
∑Fy = m*ay , ay=0
N-W = 0
N = W
N = 882 N
We replace the data in the formula (2)
Ff= μk*N = 0.351* 882 N
Ff= 309.58 N
We apply the formula (1) in x direction:
∑Fx = m*ax , ax=0
282 N - 309.58 N = 90*a
a= (282 N - 309.58 N ) / (90)
a= - 0.306 m/s²
Kinematics of the crate
Because the crate moves with uniformly accelerated movement we apply the following formula :
vf²=v₀²+2*a*d Formula (3)
Where:
d:displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
Data
v₀ = 0.850 m/s
d = 0.75 m
a= - 0.306 m/s²
We replace the data in the formula (3)
vf²=(0.850)²+(2)( - 0.306 )(0.75 )