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kozerog [31]
1 year ago
6

A 1100 kg racing car accelerates from rest at a constant rate and covers a distance of 50 m in 5 s. what is the car's accelerati

on? (in m/s2)
Physics
1 answer:
allsm [11]1 year ago
8 0

The car's acceleration, given the data from the question is 4 m/s²

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

  • Initial velocity (u) = 13 m/s
  • Distance (s) = 50 m
  • Time (t) = 5 s
  • Acceleration (a) = 9.8

<h3>How to determine the acceleration of the car</h3>

The acceleration of the car can be obtained as illustrated below:

s = ut + ½at²

50 = (0 × 5) + (½ × a × 5²)

50 = 0 + (½ × a × 25)

50 = 0 + 12.5a

50 = 12.5a

Divide both sides by 12.5

a = 50 /12.5

a = 4 m/s²

Thus, the acceleration of the car is 4 m/s²

Learn more about acceleration:

brainly.com/question/491732

#SPJ1

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A model rocket blasts off from the ground, rising straight upward with a constant acceleration that has a magnitude of 86.0 m/s2
Harman [31]
<span>When the fuel  of the rocket is consumed, the acceleration would be zero. However, at this phase the rocket would still be going up until all the forces of gravity would dominate and change the direction of the rocket. We need to calculate two distances, one from the ground until the point where the fuel is consumed and from that point to the point where the gravity would change the direction. 

Given:
a = 86 m/s^2 
t = 1.7 s

Solution:

d = vi (t) + 0.5 (a) (t^2) 
d = (0) (1.7) + 0.5 (86) (1.7)^2 
d = 124.27 m 

vf = vi + at 
vf = 0 + 86 (1.7) 
vf = 146.2 m/s (velocity when the fuel is consumed completely) 

Then, we calculate the time it takes until it reaches the maximum height.
vf = vi + at 
0 = 146.2 + (-9.8) (t) 
t = 14.92 s

Then, the second distance
d= vi (t) + 0.5 (a) (t^2) 
d = 146.2 (14.92) + 0.5 (-9.8) (14.92^2) 
d = 1090.53  m

Then, we determine the maximum altitude:
 d1 + d2 = 124.27 m + 1090.53 m = 1214.8 m</span>
5 0
3 years ago
A blacksmith heats a 1.5 kg iron horseshoe to 500 C, containing 20 kg of water at 18 C then plunges it into a bucket What is the
Tema [17]

Answer:

21.85 C

Explanation:

mass of iron = 1.5 kg, initial temperature of iron, T1 = 500 C

mass of water = 20 kg, initial temperature of water, T2 = 18 C

let T be the equilibrium temperature.

Specific heat of iron = 449 J/kg C

specific heat of water = 4186 J/kg C

Use the principle of caloriemetry

heat lost by the hot body = heat gained by the cold body

mass of iron x specific heat of iron x decrease in temperature = mass of water  x specific heat of water x increase in temperature

1.5 x 449 x (500 - T) = 20 x 4186 x (T - 18)

336750 - 673.5 T = 83720 T - 1506960

1843710 = 84393.5 T

T = 21.85 C

8 0
2 years ago
A wire with length 3.5 m and mass 0.03 kg is aligned horizontally and connected by conducting loops to two vertical frictionless
Sindrei [870]

Answer:

Current flowing in the wire is 1680 A

Explanation:

It is given length of wire l = 3.5 m

Mass of the wire m = 0.03 kg

Magnetic field B = 0.00005 Tesla

Acceleration due to gravity g=9.8m/sec^2

Mg force acting on the wire will be equal to Lorentz force acting on the wire.

Therefore mg=IBl

0.03\times 9.8=I\times 0.00005\times 3.5

I=1680A

Therefore current flowing in the wire is 1680 A

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Which lighting direction is used to create silhouettes?
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Backlighting is used to create silhouettes 

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3 bar. 1 bar normal air pressure and 2 bar for being 20 m underwater
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