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kozerog [31]
2 years ago
6

A 1100 kg racing car accelerates from rest at a constant rate and covers a distance of 50 m in 5 s. what is the car's accelerati

on? (in m/s2)
Physics
1 answer:
allsm [11]2 years ago
8 0

The car's acceleration, given the data from the question is 4 m/s²

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

  • Initial velocity (u) = 13 m/s
  • Distance (s) = 50 m
  • Time (t) = 5 s
  • Acceleration (a) = 9.8

<h3>How to determine the acceleration of the car</h3>

The acceleration of the car can be obtained as illustrated below:

s = ut + ½at²

50 = (0 × 5) + (½ × a × 5²)

50 = 0 + (½ × a × 25)

50 = 0 + 12.5a

50 = 12.5a

Divide both sides by 12.5

a = 50 /12.5

a = 4 m/s²

Thus, the acceleration of the car is 4 m/s²

Learn more about acceleration:

brainly.com/question/491732

#SPJ1

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2. From the preceding calculation, it should be obvious that to experimentally time the
marta [7]

the kinematics relations we were able to find the correct results:

  • The distance traveled as a function of time
  • The time for skull to open the paratroopers is 2.7 s

The kinematics allows finding the relationships between the position, the velocity and the acceleration of the bodies, in this case the boy is in free fall down the cliff, as he has a stopwatch in his hand he can mark the position every second that he falls, taken the downward direction as positive.

             y = y₀ + v₀ t + ½ g t²

Where y and i are the current and initial height, vo the initial velocity, g the acceleration of gravity and t the time

As it is dropped, its initial velocity is zero and we place the zero of the reference system at the top of the cliff y₀ = 0

            y = 0 + 0 + ½ g t²

            y =  ½  g t²

            y = ½ 32.16 f²

          y = 16.08 t²

Table 1 shows the distances for the first 5 seconds of the fall

 t (s)      y (ft)

  0           0

   1          16.08

   2         64.32

   3        144.72

   4        257.28

   5 402.0

In the attachment you can see a graph of distance versus time for this movement

b) We look for the time to obtain the speed of 60 mi / h

Let's reduce units of  the speed to ft / s

        v = 60 mi / h (5280 ft / 1 mi) (1h / 3600 s) = 88 ft / s

Let's use the kinematics relation

          v = v₀ + g t

           t = \frac{v -v_o}{g}

           t = \frac{88.0 - 0}{32.16}

           t = 2.7 s

Using the kinematics relations we were able to find the correct results

  • The distance traveled as a function of time
  • Tthe time for skull to open the paratroopers is 2.7 s

learn more about kinematics here:

brainly.com/question/5183024

8 0
3 years ago
What mass of ice (in g) can be melted if 27.2 kJ of thermal energy are added at the freezing point? Use molar mass = 18.02 g/mol
san4es73 [151]

Answer : The mass of ice melted can be, 3.98 grams.

Explanation :

First we have to calculate the moles of ice.

Q=\frac{\Delta H}{n}

where,

Q = energy absorbed = 27.2 kJ

\Delta H = enthalpy of fusion of ice = 6.01 kJ/mol

n = moles = ?

Now put all the given values in the above expression, we get:

27.2kJ=\frac{6.01kJ/mol}{n}

n=0.221mol

Now we have to calculate the mass of ice.

\text{Mass of ice}=\text{Moles of ice}\times \text{Molar mass of ice}

Molar mass of ice = 18.02 g/mol

\text{Mass of ice}=0.221mol\times 18.02g/mol=3.98g

Thus, the mass of ice melted can be, 3.98 grams.

3 0
4 years ago
A 6.0-kg object moving at 5.0 m/s collides with and sticks to a 2.0-kg object. After the collision the composite object is movin
gogolik [260]

Answer:

a) 23 m/s

Explanation:

  • Assuming no external forces acting during the collision, total momentum must be conserved, as follows:

       p_{o} = p_{f}  (1)

  • The initial momentum p₀, can be written as follows:

       p_{o} =  m_{1}  * v_{1o} + m_{2}* v_{2o} =   6.0 kg * 5.0 m/s + 2.0 kg * v_{2o}  (2)

  • The final momentum pf, can be written as follows:

        p_{f} = (m_{1} + m_{2} )* v_{f}  = 8.0 kg* (-2.0 m/s)  (3)

  • Since (2) and (3) are equal each other, we can solve for the only unknown that remains, v₂₀, as follows:

       v_{2o} = \frac{-6.0kg* 5m/s -8.0 kg*2.0m/s}{2.0kg}  = \frac{-46kg*m/s}{2.0kg} = -23.0 m/s  (4)

  • This means that the 2.0-kg object was moving at 23 m/s in a direction opposite to the 6.0-kg object, so its initial speed, before the collision, was 23.0 m/s.
6 0
3 years ago
Compare the practical uses and limitations of nuclear fission and fusion. Include in your answer a detailed description of the t
shtirl [24]
In fission, an atom is split into two or more smaller, lighter atoms. Fusion, in contrast, occurs when two or more smaller atoms fuse together, creating a larger, heavier atom. For the former, the energy released by fission is a million times greater than that released in chemical reactions, but lower than the energy released by nuclear fusion. On the other hand, fusion process<span> is three to four times greater than the energy released by fission. Hope this would help. Have a nice day.</span>
8 0
3 years ago
A wheel of mass 4kg is pulled up a plane inclined at 30° to the horizontal by a force of 45N applied to the axle and parallel to
Len [333]

Answer:

v = 10 m/s

Explanation:

Let's assume the wheel does not slip as it accelerates.

Energy theory is more straightforward than kinematics in my opinion.

Work done on the wheel

W = Fd = 45(12) = 540 J

Some is converted to potential energy

PE = mgh = 4(9.8)12sin30 = 235.2 J

As there is no friction mentioned, the remainder is kinetic energy

KE = 540 - 235.2 = 304.8 J

KE = ½mv² + ½Iω²

ω = v/R

KE = ½mv² + ½I(v/R)² = ½(m + I/R²)v²

v = √(2KE / (m + I/R²))

v = √(2(304.8) / (4 + 0.5/0.5²)) = √101.6

v = 10.07968...

5 0
3 years ago
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