<u>Absorb:</u>
Shine a light with known intensity into the object.
Measure the intensity of the light that comes out.
Any light that goes in but doesn't come out the other side
was absorbed by the object.
(Note: You also need to be aware of any light that bounces back from
the first side without entering the object. That light is <em><u>reflected</u></em> from it,
and can't be expected to show up at the other side.)
<u>Transmit:</u>
Any light that goes in and DOES come out the other side
was transmitted by the object.
Answer:
Aluminum (Al)
Explanation:
1. You wrap a sandwich in aluminum foil
2. Aluminum is on the periodic table.
We have that the see-saw will be balance if a weight of 
is added to Nural's side of the see-saw
From the Question we are told that
Wan’s mass is 
Nurul’s mass is 
Generally
The Will be balance when the weight on both sides of the see-saw are equal
In conclusion
The see-saw will be balance if a weight of is added to Nural's side of the see-saw
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Answer
given,
intial velocity = 504 mph
wind speed = 219 mph
at an angle of 29◦
from the data
The resultant velocity =
the magnitude of velocity
V = 703.59 m/s
direction
tan θ = 
θ = 8.676°
Answer:
241.24m
Explanation:
The height at which the shell explodes will be at the maximum height. In projectile motion, maximum height formula is expressed as:
H = u²sin²θ/2g
u is the initial speed = 70m/s
θ the angle of launch = 75°
g is the acceleration due to gravity = 9.81m/s²
Substitute the values into the formula and get H
H = 70²(sin75°)/2(9.81)
H = 4900sin75°/19.62
H = 4900*0.9659/19.62
H = 4733.037/19.62
H = 241.24m
Hence the height at which the shell explodes is 241.24m
