Answer:
m = 12.05 kg
Explanation:
Spring constant in K, N/m
K = 200/10* 100
K = 2000 N/m
Angular Frequency = sqrt (Spring constant / (Mass )
ω = 2 π f
ω = 2π* 2.05 Hz = 12.8805 rad/s
ω^2 = Spring constant / Mass
Mass= Spring constant / ω^2
ω^2 = 165.907 rad^2/s^2
m = 2000 (N/m)/165.907 (rad^2/s^2)
m = 12.05 kg
Answer:
Hiiiiiiii........where r u frm??
Answer:
s = 23.72 m
v = 21.56 m/s²
Explanation:
given
time to reach the ground (t) = 2.2 second
we know that
a) s = u t + 0.5 g t²
u = 0 m/s
g = 9.8 m/s²
s = 0 + 0.5 × 9.8 × 2.2²
s = 23.72 m
b) impact velocity
v = √(2gh)
v = √(2× 9.8 × 23.72)
v = √464.912
v = 21.56 m/s²
<span>D. sill
A sill forms when hot magma squeezes between layers of rock to form a hardened sheet of rock. A sill is basically a tabular sheet intrusion between old layers of sedimentary rock, volcanic beds, or in the direction of foliation inherent in metamorphic rock. The word sill means a concordant intrusive sheet.</span>
Explanation :
It is given that,
Diameter of the coil, d = 20 cm = 0.2 m
Radius of the coil, r = 0.1 m
Number of turns, N = 3000
Induced EMF,
Magnitude of Earth's field,
We need to find the angular frequency with which it is rotated. The induced emf due to rotation is given by :
So, the angular frequency with which the loop is rotated is 159.15 rad/s. Hence, this is the required solution.