Answer:
Explanation:
The Sierra Nevada mountain range is a product of the collision of two tectonic plates: the westward-moving North American Plate and what at the time was the Farallon Plate, which ground slowly under the North American Plate, eventually sliding entirely into the Earth's mantle
Lewis structure cannot show the numbers of valences
Answer:
The number of chlorine atoms present in units of gold III chloride is
Explanation:
Formula of Gold (III) chloride:
<em>Avogadro Number</em> : Number of particles present in <u>one mole</u><u> </u>of a substance.
Using,
= 1 mole(0.9999 , nearly equal to 1 )
The given Gold III chloride sample is 1 mole in amount.
= 1 mole of
In this Sample,
1 mole of will give = 3 mole of Chlorine atoms
1 mole of Cl contain =
3 mole of Cl contain =
3 mole of Cl contain =
So,
The number of chlorine atoms present in units of gold III chloride is
Answer:
- The annual cost for electricity to power a lampost for 7.00 h per day with a 100 W incandescent bulb is $ 40.89.
- The annual cost for electricity to power the same lampost for the same time with an energy efficient 25 W fluorescent bulb is $ 10.22.
So, you can save $ 40.89 - $ 10.22 = $ 30.67 per each lampost if you replace the incadescent bulb with the energy efficient fluorescent bulb.
Explanation:
kW.h means kilowatt.hour and is a unit of energy derived from the definition of power.
The definition of power is energy per time:
Thus, you get:
For the units, you get:
- [Energy] = [Power] [time] = KW.h.
<u>1. Calculate the energy used by the 100 W incandescent light bulb that is used 7.00 h per day, in a year (365 days).</u>
- E = Power × time = 100 W × 7.00 h / day × 365 day / year × 24 h= 255,500 W.h/year
- Divide by 1,000 to convert to kW: 255.5 kW.h/year
<u />
<u>2. Calculate the energy used by the 25 W flourescent bulb:</u>
- E = 25 W × 7.00 h / day × 365 day / year × 24 h= 63,875 W.h/year
- Divide by 1,000 to convert to kW: 63.875 kW.h/year
<u>3. Now, you can calculate both costs:</u>
- Cost per year = cost per kW.h times number of kW.h per year
<u>100 W bulb:</u>
<u />
- $ 0.16/ kW.h × 255.55 kW.h/ year = $ 40.89 / year
<u>25 W bulb:</u>
- $ 0.16/ kW.h × 63.875 kW.h/ year = $ 10.22 / year
Answer:
I'm not sure which bond stores the most energy but the ionic bond is stronger than the covalent bond.
Explanation: