Елементите от IА и IIА групи на Периодичната система

Serjik [45]

Ecological succession is the steady and gradual change in a species of a given area with respect to the changing environment. it is a predictable change and is an inevitable process of nature al all the biotic components have to keep up with the changes in our environment.

3 0

3 years ago

How many molecules are present in each sample?8.55 mol SO2 :molecules SO2 0.603 mol CO :molecules CO a sample of NH3 containing

sineoko [7]

Answer:

- 5.15×10²⁴ molecules of sulfur dioxide

- 3.63×10²³ molecules of carbon monoxide

- 6.02×10²³ molecules of ammonia

Explanation:

We begin from the relation that 1 mol of molecules contains NA of molecules

NA = 6.02×10²³

Now, we make rules of three:

1 mol has 6.02×10²³ molecules, therefore:

8.55 moles of SO₂ must have (8.55 . NA) / 1 = 5.15×10²⁴ molecules of dioxide

0.603 moles of CO must have (0.603 . NA) / 1 = 3.63×10²³ molecules of monoxide

Avogadro's Number of molecules of NH₃ are 6.02×10²³ molecules of ammonia

3 0

3 years ago

LOS AMOOOO 1 AL 40 COMENTÉN

OleMash [197]

Answer:

0 ni siquiera te conozco

Explanation:

6 0

3 years ago

PLEASE HELP ME SOLVE THIS.Thank you so much!

Tju [1.3M]

Answer: The coefficients for the given reaction species are 1, 6, 2, 3.

Explanation:

The given reaction equation is as follows.

$Cr_{2}O^{2-}_{7} + Cl^{-} \rightarrow Cr^{3+} + Cl_{2}$

Now, the two half-reactions can be written as follows.

Reduction half-reaction: $Cr_{2}O^{2-}_{7} + 3e^{-} \rightarrow Cr^{3+}$

This will be balanced as follows.

$Cr_{2}O^{2-}_{7} + 14H^{+} + 6e^{-} \rightarrow 2Cr^{3+} + 7H_{2}O$ ... (1)

Oxidation half-reaction: $Cl^{-} \rightarrow Cl_{2} + 1e^{-}$

This will be balanced as follows.

$6Cl^{-} \rightarrow 3Cl_{2} + 6e^{-}$ ... (2)

Adding both equation (1) and (2) we will get the resulting equation as follows.

$Cr_{2}O^{2-}_{7} + 14H^{+} + 6Cl^{-} \rightarrow 2Cr^{3+} + 3Cl_{2} + 7H_{2}O$

Thus, we can conclude that coefficients for the given reaction species are 1, 6, 2, 3.

6 0

3 years ago

Consider dissolving sugar in water and magnesium sulfate in water. is any new substance being produced? what happens after sodiu

Olenka [21]

Answer:

Here's what I get

Explanation:

1. Sugar

(a) Dissolving in water

The white solid dissolves in water to give a colourless solution. There is no evidence that a new substance is being produced.

(b) Addition of sodium hydroxide

Adding the colourless solution of sodium hydroxide to the colourless sugar solution gives a colourless solution. There is no evidence that a new substance is being produced.

2. Magnesium sulfate

(a) Dissolving in water

The colourless crystals dissolve in water to give a colourless solution. There is no evidence that a new substance is being produced.

(b) Addition of sodium hydroxide

Adding the colourless solution of sodium hydroxide to the colourless solution of magnesium sulfate gives a white precipitate (see image). This is evidence that a new substance is being produced.

8 0

3 years ago