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valkas [14]
2 years ago
15

The equilibrium for the reaction between (ch3)2nh a weak base

Chemistry
1 answer:
nadezda [96]2 years ago
7 0

The equilibrium for the dissolution of the weak base is ;(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH3^+(aq) + OH^-(aq)

<h3>What is a weak base?</h3>

A weak base is one that does not ionize completely in solution. As such, a weak base will have a very low base dissociation constant Kb reflecting its minimal dissociation in solution.

The question is incomplete hence we are are unable to work out the equilibrium but in solution it will look like this;

(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH3^+(aq) + OH^-(aq)

Learn more about weak base: brainly.com/question/4131966

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Given

The data in the table

Required

Follow the steps appended to the question;

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Mean = Summation of lengths divided by number of teams;

Mean = \frac{2.65 + 2.75 + 2.80 + 2.77 + 2.60 + 2.65 + 2.68}{7}\ cm

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