Answer:
Explanation:
The average force is defined as the mass of the body multiplied by its average velocity over the contact time. According to the third Newton's law, the magnitude of the average force exerted on the wall by the ball is equal to the magnitude of the average force exerted on the ball by the wall. Thus:
Answer:
shown below
Explanation:
2 x 10⁷ as a number is 20,000,000
20,000,000 - 10 = 19,999,990
It went 19,999,990 m/h
in km/h:
19,999,990 / 1000 = 19,999.99 km/h
in km/s
19,999,990 / 3,600,000 = ~5.56 km/s
in m/s
19,999,990 / 3600 = ~5555.56 m/s
Answer:
B) laws that require scientists to research certain things
Answer:
25.7 N
44.8 N
Explanation:
Draw a free body diagram of the block. There are three forces: weight force mg pulling down, buoyancy force ρVg pushing up, and normal force N pushing up.
Sum of forces in the y direction:
∑F = ma
N + ρVg − mg = 0
N = mg − ρVg
N = (3.5 kg) (9.8 m/s²) − (1000 kg/m³) (3.5 kg / 4000 kg/m³) (9.8 m/s²)
N = 25.7 N
The water pushes up on the block with a buoyancy force of ρVg. According to Newton's third law, the block pushes back down on the water with an equal force of ρVg.
The other forces are weight force Mg pulling down, and normal force N pushing up.
Sum of forces in the y-direction:
∑F = ma
N − ρVg − Mg = 0
N = Mg + ρVg
N = (1.4 kg + 2.3 kg) (9.8 m/s²) + (1000 kg/m³) (3.5 kg / 4000 kg/m³) (9.8 m/s²)
N = 44.8 N
Answer:
F = -2527.35 N
Explanation:
Given,
mass per unit time = 58.1 Kg/s
Speed of the water = 43.5 m/s
Final momentum = 0 kg/s
Force = Change in momentum
F = Final momentum - initial momentum
F = 0 - initial momentum
F = -2527.35 N
Hence, the Force exerted is equal to F = -2527.35 N