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Nataly_w [17]
3 years ago
15

If you decrease the mass of an object to half of the original, how does the pressure change?

Physics
2 answers:
fiasKO [112]3 years ago
8 0

Answer:

When a hockey puck is at rest, the net force on it

(gravity and the support force) is balanced, so the puck

is in equilibrium.

Hit the puck (that is, apply an unbalanced force to it)

and the puck experiences a change in motion—it

accelerates.

Apply another force by striking the puck again, and the

puck’s motion changes again.

Andrei [34K]3 years ago
8 0

Answer:

The acceleration is equal to the net force divided by the mass. If the net force acting on an object doubles, its acceleration is doubled. If the mass is doubled, then acceleration will be halved. If both the net force and the mass are doubled, the acceleration will be unchanged.

Explanation:

<h2><em>hope</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>helpful</em><em> </em><em>for</em><em> </em><em>you</em><em> </em></h2><h2><em>keep</em><em> </em><em>smiling</em><em> </em></h2>
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The refractive index for glycerine is n_g=1.473, while for air it is n_a = 1.00.

When the light travels from a medium with greater refractive index to a medium with lower refractive index, there is a critical angle over which there is no refraction, but all the light is reflected. This critical angle is given by:
\theta_c = \arcsin ( \frac{n_2}{n_1} )
where n1 and n2 are the refractive indices of the two mediums. If we susbtitute the refractive index of glycerine and air in the formula, we find the critical angle for this case:
\theta_c = \arcsin ( \frac{1.00}{1.473} )=42.8^{\circ}
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3 years ago
When can a high speed velocity cause damage?'
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Answer:

50 Mph.

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Tests reveal that a normal driver takes about 0.75 s before he or she can react to a situation to avoid a collision. It takes ab
nata0808 [166]

To solve this problem we will apply the linear motion kinematic equations. On these equations we will define the speed as the distance traveled in a space of time, and that speed will be in charge of indicating the reaction rate of the individual. In turn, using the ratio of speed, position and acceleration, we will clear the position and determine the distance necessary for braking.

The relation to express the velocity in terms of position for constant acceleration is as follows

v^2 = u^2+2a(s-s_0)

Here,

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v= Final velocity

a = Acceleration

s_0 = Initial position

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PART 1) Calculate the displacement within the reaction time

d = vt

d = (44)(0.75)

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In this case we can calculate the shortest stopping distance

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s = 517ft

PART 2)

PART 1) Calculate the displacement within the reaction time

d = vt

d = (44)(3)

d = 132ft

In this case we can calculate the shortest stopping distance

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s = 616ft

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Answer:

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