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Amanda [17]
3 years ago
8

A person is pushing a book lying on a table. Identify the different forces that act on

Physics
2 answers:
BaLLatris [955]3 years ago
3 0

Explanation:

There are two forces acting upon the book. One force - the Earth's gravitational pull - exerts a downward force. The other force - the push of the table on the book (sometimes referred to as a normal force) - pushes upward on the book.

sveticcg [70]3 years ago
3 0

There are mainly 3 forces which acts on a book.

Listed below are the forces and their points:-

• <u>Earth's Gravitational force of attraction</u>- Usually, we may not consider or notice this force, but when a book falls, we understand this, because the book falls due to this gravitational force.

• <u>Force exerted on book while pushing it</u>- While we push a book, we apply Push Force, due to which the book moves on the pushing it on a table.

• <u>Frict</u><u>ional</u><u> </u><u>Force</u>- We notice that while pushing a book, it does not continuously move in motion. At a certain distance, this Frictional force increases and therefore, the book comes to a halt.

<em>Location-</em> <em>Opposite of exerted force in all directions</em>

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Answer: 0.001 m

Explanation:

In order to get the máximum height reached by the iron block, we can use the energy conservation principle, as all the kinetic energy impressed upon the iron blck by the rubber bullet during the collision, becomes gravitational potential energy, as follows:

½ m v2 = m. g. h (1)

We don´t know the value of v, but if we look to the collision, and we asume no external forces act during it, the total momentum must be conserved.

The initial momentum, as the block is at rest, is just the one due to the rubber bullet:

P1 = mb . vb = 0.025 kg. 50 m/s = 1.25 kg. m/s

The final momemtum, is just the sum of the one due to the bullet (after being bounced back) and the one for the iron block:

P2 = mb . vfb  + mib . vib= 0.025 Kg. (-35 m/s) + 15 Kg.vib

As we have already said, P1 = P2, so we can write the following equation:

0.025 Kg. (-35 m/s) + 15 Kg. vib = 1.25 Kg. m/s.

Solving for vib, we have:

vib = 0.14 m/s

Now, we can replace this value in the equation (1) above:

½ . 15 Kg. (0.14)2  (m/s)2 = 15 Kg. 9.8 m/s2. H

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Explained

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