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Nat2105 [25]
3 years ago
11

At a given location from a source charge, the electric field______________.a. strength is dependent on the source charge and the

charge that is at the given location. points away from the source charge, regardless of the sign of the source b. points away from the source charge, if the source charge is positive. c. strength is only dependent on the source charge.d. points toward the source charge, if the source charge is negative.
Physics
1 answer:
noname [10]3 years ago
3 0

Answer:

b. The electric field points away from the source charge, if the source charge is positive

d. The electric field points toward the source charge, if the source charge is negative.

Explanation:

A positive source charge would create an electric field that would exert a repulsive effect upon a positive test charge. Thus, the electric field vector would always be directed away from positively charged objects. On the other hand, a positive test charge would be attracted to a negative source charge. Therefore, electric field vectors are always directed towards negatively charged object.

Also electric field strength depends only on test charge

The correct options include b and d

The electric field points away from the source charge, if the source charge is positive.

Also, the electric field points toward the source charge, if the source charge is negative.

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A wire of length 5mm and Diameter 2m extends by 0.25 when a force of 50N was use. calculate the
bazaltina [42]

Answer and Explanation:

Data provided in the question

Force = 50N

Length = 5mm

diameter = 2.0m = 2\times 10^{-3}

Extended by = 0.25mm = 0.25\times 10^{-3}

Based on the above information, the calculation is as follows

a. The Stress of the wire is

= \frac{force\ applied}{area\ of \ circle}

here area of circle = perpendicular to the are i.e cross-sectional  i.e

= \frac{\pi d^{2}}{4}

= \frac{\pi(2\times 10^{-3})^2}{4}

Now place these above values to the above formula

= \frac{4\times 50}{\pi\times 4 \times 10^{-6}} \\\\ = \frac{50}{\pi}

= 15.92 MPa

As 1Pa = 1 by N m^2

So,

MPa = 10^6 N m^2

b. Now the strain of the wire is

= \frac{Change\ in\ length}{initial\ length} \\\\ = \frac{0.25\times 10^{-3}}{5}

= 5 \times 10^{-5}

3 0
4 years ago
Hello please help i’ll give brainliest
ser-zykov [4K]

The correct answer is B.Antartica and Australia were one landmass millions of years ago.

5 0
3 years ago
An atom with two protons, three neutrons and two electrons would have a mass of about how many atomic mass units?
Katarina [22]
The answer is 5 amu.
8 0
3 years ago
Sonar is used to map the ocean floor. if an ultrasonic signal is received 3.3 s after it is emitted, how deep is the ocean floor
Goryan [66]
The speed of sound in fresh water is 1482m/s. 
It says ocean floor, so we should a little bit more accurate, and use the fact that the speed of sound in salt water (that has no bubbles) is 1560m/s. 
speed = distance / time 
Therefore Distance = speed x time = 1560 x 3.3 = 5158m 
The sonar wave is sent out by the boat, reflected off the seafloor, and then is received back at the boat on the surface. So the distance 5148m is the distance from the boat to the sea bottom and then back up to the boat again. 
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6 0
3 years ago
Last week we investigated the black hole at the center of our galaxy, with massMX= 8.5×1036kg. An object whose size is on the or
swat32

Answer:

d=2.38*10^{13}m

Explanation:

We know the mass of the hole, so we define as,

M_x= {8.5*10^{36}}kg

For which centripetal force is equal to gravitational force

\frac{mv^2}{r}=\frac{GMm}{d^2}

Angular velocity is equal to v/r,

w^2r=\frac{6.67*10^{-11}*8.5*10^{36}}{d^2}

As r=1 and w=1, we clear to d,

d^2=5.6695*10^{26}m

d=2.38*10^{13}m

6 0
3 years ago
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