All categories

3 years ago

HELP ASAP

1 answer:

4 0

Equilibrium constant of a reaction is the ratio of concentrations of the products and the reactants when the reaction is in equilibrium. This value is independent of the concentrations since the conditions are at equilibrium instead it depends on ionic strength and temperature.

First, we write the equilibrium expression.

K = [H2S]^2 / [H2]^2 x [S2]
K = (0.725^2) / [(0.208^2) (1.13 x 10^-6)]
K = 10751545.56 or 1.08 x 10^7

Thus, the answer is A.

You might be interested in

Lucien drove for 24 straight hours going 960 KM. What was his average speed?

madreJ [45]

Answer:

40 KM an hour.

Explanation:

7 0

3 years ago

Read 2 more answers

Newton's first law of motion, or the law of inertia, states:

Lady bird [3.3K]

Answer:

when he collided with the passerby

Explanation:

8 0

3 years ago

Determine the change in entropy for 2.7 moles of an ideal gas originally placed in a container with a volume of 4.0 L when the c

olchik [2.2K]

Answer:

The value of entropy change for the process $dS = 0.009 \frac{KJ}{K}$

Explanation:

Mass of the ideal gas = 0.0027 kilo mol

Initial volume $V_{1}$ = 4 L

Final volume $V_{2}$ = 6 L

Gas constant for this ideal gas ( R ) = $R_{u} M$

Where $R_{u}$ = Universal gas constant = 8.314 $\frac{KJ}{Kmol K}$

⇒ Gas constant R = 8.314 × 0.0027 = 0.0224 $\frac{KJ}{K}$

Entropy change at constant temperature is given by,

$dS = R log _{e} \frac{V_{2}}{V_{1}}$

Put all the values in above formula we get,

$dS = 0.0224 log _{e} [\frac{6}{4}]$

$dS = 0.009 \frac{KJ}{K}$

This is the value of entropy change for the process.

6 0

3 years ago

How many moles of a gas sample are in a 10.0 L container at 298 K and 203 kPa? (Use the ideal gas law PV = nRT with R = 8.31 L-k

weeeeeb [17]

Ideal gas law: PV = nRT

P-pressure
V-volume
n-number of moles(m/M)
R-constant
T- temperature

State given info:
V=10L
T=298k
P=203kPa
R=8.31(only for kPa, for pressure at atm use 0.08206)

Sub in:
(203kPa)(10L)=n(8.31)(298)

Rearrange:
n= (203)(10) / (8.31)(298)
n = 0.819745mol in gas sample

8 0

3 years ago

How many single covalent bonds does beryllium form in BeCl2?

Tanzania [10]

Answer:

what I'm not really understand this question

3 0

3 years ago

Read 2 more answers