Using the normal distribution, it is found that 1851 people would have an IQ less than 115.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean 
and standard deviation 
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
The proportion of IQ scores less than 115 is the <u>p-value of Z when X = 115</u>, hence:
Z = 1
Z = 1 has a p-value of 0.8413.
Out of 2200 people:
0.8413 x 2200 = 1851.
More can be learned about the normal distribution at brainly.com/question/27643290
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Answer:
6
Step-by-step explanation:
P(6) = ⅙
Expected no. of trials for first 6:
1 ÷ (1/6) = 6
Answer: so i dont but hopefully someone cane help you
Step-by-step explanation:
Answers
Part 1
Arithmetic sequence is a sequence by which the next term is found by adding a constant number. It can be a positive number or a negative number. This number is called the common difference. On the other hand, a geometric sequence is one whose next term is found by multiplying the previous term with a constant (common ratio).
Part 2
Sequences are useful in our daily lives as well as in higher mathematics. For example, the
interest portion of monthly payments made to pay off an automobile or home loan, and the list of maximum daily temperatures in one area for a month are sequences.
<u>Example: arithmetic sequence</u>
A child building a tower with blocks uses 15 for the bottom row. Each row has 2 fewer blocks than the previous row. Suppose that there are 8 rows in the tower. Find an for n = 8.
The number of blocks in each row forms an arithmetic sequence with a₁ = 15 and d= −2. The formula to be used is an = a₁ + (n − 1)d.
<u>Example: geometric sequence </u>
An insect population is growing in such a way that each new generation is 1.5 times as large as the previous generation. Suppose there are 100 insects in the first generation. How many will there be in the fifth generation?
The population can be written as a geometric sequence with a₁ as the first generation population, a₂ as the second-generation population, and so on. Then the fifth generation population will be a₅. The formula to be used is an = a₁×r⁽ⁿ⁻¹⁾
A ratio equivalent to 3:11 will be multiplying each term by a common term. Eg 3 x 2 : 11 x 2 = 6:22
