Answer:
H = 0.673
Explanation:
given,
side of cubical crate = 0.74
weight of the crate = 600 N
magnitude of force = 330 N
the Horizontal distance of its Center of mass
= 0.74/2
= 0.37
Let the required Height be H
By Balancing the Torques, we get
H x 330 N = 0.37 x 600
330 H = 222
H = 0.673
hence, the height above the floor where force is acting is equal to 0.673 m
Answer:
10800
Explanation:
if someone runs 720 miles every minutes they will run 10,800 miles in 15 minutes
Answer:
Do neither of these things ( c )
Explanation:
For length contraction : Is calculated considering the observer moving at a speed that is relative the object at rest applying this formula
L = (l) 
where l = Measured distance from object at rest, L = contracted measured in relation to the observer , v = speed of clock , c = speed of light
you will do neither of these things because before you can make such decisions who have to view the object in this case yourself from a different frame from where you are currently are, if not your length and width will not change hence you can't make such conclusions/decisions .
The maximum speed the mass can have before it breaks is 2.27 m/s.
The given parameters:
- <em>maximum mass the string can support before breaking, m = 17.9 kg</em>
- <em>radius of the circle, r = 0.525 m</em>
The maximum speed the mass can have before it breaks is calculated as follows;

Thus, the maximum speed the mass can have before it breaks is 2.27 m/s.
Learn more about maximum speed of horizontal circle here:brainly.com/question/21971127