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riadik2000 [5.3K]

2 years ago

15

Electric kettle with the resistance of 20-02.is used-to-heat:4 kg of water. If

1 answer:

jeka942 years ago

5 0

The guy that answered this is fake and he’s doing it for free points so
Just repost it and hope he doesn’t find it

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Hydrogen cyanide is poisonous liquid that has a faint almond like smell. one molecule of hydrogen cyanide is made up of one hydr

Lisa [10]

"<span>H-C=N:" is the one answer among the choices given in the question that shows the correct dot diagram. The correct option among all the options that are given in the question is the fourth option or option "D". The other choices can be neglected. I hope that this is the answer that has come to your help.</span>

3 0

2 years ago

Read 2 more answers

An electron with a charge of -1.6 × 10-19 coulombs experiences a field of 1.4 × 105 newtons/coulomb. What is the magnitude of th

neonofarm [45]

Answer:

Electric force, $F=2.24\times 10^{-14}\ N$

Explanation:

It is given that,

Charge on an electron is $-1.6\times 10^{-19}\ C$

Electric field, $E=1.4\times 10^5\ N/m$

We need to find the magnitude of the electric force on this electron due to this field. The electric force is given by :

$F=qE\\\\F=1.6\times 10^{-19}\times 1.4\times 10^5\\\\F=2.24\times 10^{-14}\ N$

So, the electric force is $2.24\times 10^{-14}\ N$ .

6 0

2 years ago

If humans are the most complex creature, does that mean they have the most number of chromosomes?

Bezzdna [24]

Yes. Either way though, humans have more chromosomes than any other species.

5 0

3 years ago

Read 2 more answers

An automobile engine has an efficiency of 22.0% and produces 2510 J of work. How much heat is rejected by the engine

katrin [286]

Answer:

If efficiency is .22 then W = .22 * Q where Q is the heat input

Heat Input Q = 2510 / .22 = 11,400 J

Heat rejected = 11.400 - 2510 = 8900 J of heat wasted

Also, 8900 J / (4.19 J / cal) = 2120 cal

5 0

3 years ago

Automobile traveling at 65 mph constant on the road described below. Find rate at which radar must rotate when theta = 15 deg. A

Finger [1]

Answer:

The rate at which radar must rotate is 0.335 rad/s.

Explanation:

Given that,

Velocity = 65 m/h = 29.0576 m/s

Angle = 15°

Suppose, the radius given by

$r=(100\cos2\theta)\ m$

We need to calculate the rate at which radar must rotate

Using formula of linear velocity

$v=r\omega$

$\omega=\dfrac{v}{r}$

Where, v = velocity

r = radius

Put the value into the formula

$\omega=\dfrac{29.0576}{100\cos30}$

$\omega=0.335\ rad/s$

Hence, The rate at which radar must rotate is 0.335 rad/s.

3 0

3 years ago