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3 years ago

Negatively charged particle that orbits the nucleus

Physics

1 answer:

Ede4ka [16]3 years ago

6 0

Answer: Electrons.

Explanation:

Electrons are the negatively charged particles that orbit the nucleus of an atom. Protons, on the other hand, are the positively charged particles that orbit the nucleus of an atom.

in the picture, the protons and neutrons are “in” the nucleus and you’ll also see the the electrons are orbiting all around the nucleus.

If this helped please mark me brainliest.

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A gas is collected over water at 20C in a eudiometer tube until the pressure is equilibrated with the atmospherica pressure. Wha

solong [7]

Let's assume that the pressure given is 771 torr.

Answer:

747.44 torr

Explanation:

The eudiometer tube is a setup that collects gas in a liquid (generally water). After the thermal equilibrium, the gas becomes in equilibrium with the vapor of water above the liquid.

By Dalton's law, the total pressure of a mixture is the sum of the partial pressure of its components. The partial pressure is the pressure that the gas would have at the same conditions if it was alone. So, the pressure of the dry gas is its partial pressure.

The total pressure is the barometric pressure, and the partial pressure of the water vapor at 20°C is 23.56 torr (the value can be found at a thermodynamic table). So, the pressure of the dry gas (P) is:

771 = 23.56 + P

P = 771 - 23.56

P = 747.44 torr

6 0

3 years ago

Terangkan lokasi zaman prasejarah di Malaysia

Andreas93 [3]

Answer:

Panget ka wala kang alam at Bo bo ka mamatay ka sige patay kana

Done That's the answer

5 0

3 years ago

A body cycles continously through a distance of 10km in 5 mins. calculate its average speed

stira [4]

Answer:

distance=10km=10*1000=10000m

time=5min=5*60=300sec

average speed=distance/time

= 10000/300=33.33m/s

Explanation:

3 0

3 years ago

PLEASE HELP!!!

anzhelika [568]

The net force that is applied to the passenger during the elevator acceleration is 218.75 N.

<h3>What is net force?</h3>

This is the single force obtained from the combinatiion of two or more forces

To calculate the net force that is applied to the passenger during the elevator's acceleration, we use the formula below.

Formula:

F = m(v-u)/t............ Equation 1

Where:

F = force
m = mass
v = Final velocity
u = initial velocity
t = time.

From the question,

Given:

m = 70 kg
u = 0 m/s
v = 12.5 m/s
t = 4 s

Substitute these values into equation 1

F = 70(12.5-0)/4

F = 218.75 N

Hence, The net force that is applied to the passenger during the elevator acceleration is 218.75 N.

Learn more about net force here: brainly.com/question/13370981

7 0

2 years ago

A stunt driver wants to make his car jump over 8 cars parked side by side below a horizontal ramp.

Genrish500 [490]

<u>Answer:</u>

a) Minimum speed must he drive off the horizontal ramp = 39.78 m/s

b) Minimum speed must he drive off the horizontal ramp with 7° above the horizontal = 23.93 m/s

<u>Explanation:</u>

a) The height of ramp = 1.5 meter

Horizontal distance he must clear = 22 meter

The car is having horizontal motion and vertical motion. In case of vertical motion the acceleration on the car is acceleration due to gravity.

We have equation of motion, $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In case of vertical motion initial velocity = 0 m/s, acceleration = 9.8 $m/s^2$ , we need to calculate time when displacement = 1.5 meter.

$1.5=0*t+\frac{1}{2} *9.8*t^2\\ \\ t = 0.553 seconds$

So the car has to cover a distance of 22 meter in 2.119 seconds.

So minimum speed required = 22/0.553 = 39.78 m/s

Minimum speed must he drive off the horizontal ramp = 39.78 m/s

b) When the take of angle is 7⁰ the vertical speed of car is not zero = V sin 7 = 0.122 V

So the in case of vertical motion we have initial velocity = 0.122 V, S = -1.5 meter( below ramp), acceleration = -9.8 $m/s^2$

Substituting

$-1.5=0.122V*t-\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2-0.122Vt-1.5=0$

In case of horizontal motion

Horizontal speed of car = V cos 7 = 0.993V

So it has to travel 22 meter in t seconds

0.993Vt = 22, Vt = 22.155 m

Substituting in the equation $4.9t^2-0.122Vt-1.5=0$

We will get $4.9t^2-0.122*22.155-1.5=0\\ \\ t = 0.926 seconds$

Speed required = 22.155/0.926 = 23.93 m/s

Minimum speed must he drive off the horizontal ramp with 7° above the horizontal = 23.93 m/s

7 0

4 years ago