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1 answer:
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A) The kinetic energy of an object is given by:
where m is the mass of the object, and v its speed. For the lion in our problem, m=45 kg and v=14.2 m/s, so its kinetic energy is
b) the increase in gravitational potential energy of the lion is given by:
where g is the gravitational acceleration, and
is the increase in altitude of the lion. In this problem, 
, so the increase in gravitational potential energy is
c) When the fox reaches the top of the tree, its gravitational potential energy is
As it jumps, its kinetic energy is
So the total mechanical energy of the fox as it jumps is
where m is the mass of the object, and v its speed. For the lion in our problem, m=45 kg and v=14.2 m/s, so its kinetic energy is
b) the increase in gravitational potential energy of the lion is given by:
where g is the gravitational acceleration, and
c) When the fox reaches the top of the tree, its gravitational potential energy is
As it jumps, its kinetic energy is
So the total mechanical energy of the fox as it jumps is
Answer:
f = 5.3 Hz
Explanation:
To solve this problem, let's find the equation that describes the process, using Newton's second law
∑ F = ma
where the acceleration is
a =
B- W = m \frac{d^2 y}{dt^2 }
To solve this problem we create a change in the reference system, we place the zero at the equilibrium point
B = W
In this frame of reference, the variable y' when it is oscillating is positive and negative, therefore Newton's equation remains
B’= m
the thrust is given by the Archimedes relation
B = ρ_liquid g V_liquid
the volume is
V = π r² y'
we substitute
- ρ_liquid g π r² y’ = m \frac{d^2 y'}{dt^2 }
this differential equation has a solution of type
y = A cos (wt + Ф)
where
w² = ρ_liquid g π r² /m
angular velocity and frequency are related
w = 2π f
we substitute
4π² f² = ρ_liquid g π r² / m
f =
calculate
f =
f = 5.3 Hz
Answer:
The maximum electric power output is
Explanation:
From the question we are told that
The capacity of the hydroelectric plant is
The level at which water is been released is
The efficiency is 0.90
The electric power output is mathematically represented as
Where is the potential energy at level h which is mathematically evaluated as
and is the potential energy at ground level which is mathematically evaluated as
So
here
where V is volume and is density of water whose value is
So
substituting values
The maximum possible electric power output is
substituting values