Answer: 25.89g of O2 (g)
Explanation:
We begin by finding the molar mass of compounds of interest in the given equation. 2 KClO3 ⟶ 2 KCl + 3 O 2
1 mole of KCLO3 = 39 .10 + 35.5 + (3x16) = 122.55g, 2Moles would be 2 x 122.5 = 245.1g
1 mole Oxygen gas = 32g, 3 moles would be, 3 x 32= 96g
According to the equation;
245.1g of KCLO3 produces 96g of O2 (g)
If 1g of KCLO3 produces 96÷245.1 of O2 (g) from heating.
66.1g of KCLO3 would produce; 96÷245.1 x 66.1 = 25.89g of O2 (g) from heating.
Answer:
i think its CaCO3 + 2HCl → CaCl2 + H2O + CO2
Explanation:
I believe the answer is 20
P1V1=P2V2
SO
2X0.140=P2X4.50
P2=2X0.140/4.50
P2=0.0622 atm
The relative atomic mass of Ne = 20.2. Therefore 20.2 g of neon contains 6.022 × 1023 Ne atoms.
