Answer: Step 1, Isomerase.
Explanation:
Form the version of palmitic acid in the step one by changing the double bond within alpha and beta carbon by Isomerase.
B and C are Isomers, the molecule only differ in configuration.
<u>Answer:</u> The longest wavelength of light is 656.5 nm
<u>Explanation:</u>
For the longest wavelength, the transition should be from n to n+1, where: n = lower energy level
To calculate the wavelength of light, we use Rydberg's Equation:
![\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%3DR_H%5Cleft%28%5Cfrac%7B1%7D%7Bn_i%5E2%7D-%5Cfrac%7B1%7D%7Bn_f%5E2%7D%20%5Cright%20%29)
Where,
= Wavelength of radiation
= Rydberg's Constant = ![1.096776\times 10^7m^{-1}](https://tex.z-dn.net/?f=1.096776%5Ctimes%2010%5E7m%5E%7B-1%7D)
= Higher energy level = ![n_i+1=(2+1)=3](https://tex.z-dn.net/?f=n_i%2B1%3D%282%2B1%29%3D3)
= Lower energy level = 2 (Balmer series)
Putting the values in above equation, we get:
![\frac{1}{\lambda }=1.096776\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{3^2} \right )\\\\\lambda =\frac{1}{1.5233\times 10^6m^{-1}}=6.565\times 10^{-7}m](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%20%7D%3D1.096776%5Ctimes%2010%5E7m%5E%7B-1%7D%5Cleft%28%5Cfrac%7B1%7D%7B2%5E2%7D-%5Cfrac%7B1%7D%7B3%5E2%7D%20%5Cright%20%29%5C%5C%5C%5C%5Clambda%20%3D%5Cfrac%7B1%7D%7B1.5233%5Ctimes%2010%5E6m%5E%7B-1%7D%7D%3D6.565%5Ctimes%2010%5E%7B-7%7Dm)
Converting this into nanometers, we use the conversion factor:
![1m=10^9nm](https://tex.z-dn.net/?f=1m%3D10%5E9nm)
So, ![6.565\times 10^{-7}m\times (\frac{10^9nm}{1m})=656.5nm](https://tex.z-dn.net/?f=6.565%5Ctimes%2010%5E%7B-7%7Dm%5Ctimes%20%28%5Cfrac%7B10%5E9nm%7D%7B1m%7D%29%3D656.5nm)
Hence, the longest wavelength of light is 656.5 nm
Answer:
All of the physical and biological factors in it's environment, I think this is the answer, but I might be wrong.
Explanation:
I learned it in my school's Science class
Hey there!
Values Ka1 and Ka2 :
Ka1 => 8.0*10⁻⁵
Ka2 => 1.6*10⁻¹²
H2A + H2O -------> H3O⁺ + HA⁻
Ka2 is very less so I am not considering that dissociation.
Now Ka = 8.0*10⁻⁵ = [H3O⁺] [HA⁻] / [H2A]
lets concentration of H3O⁺ = X then above equation will be
8.0*10−5 = [x] [x] / [0.28 -x
8.0*10−5 = x² / [0.28 -x ]
x² + 8.0*10⁻⁵x - 2.24 * 10⁻⁵
solve the quardratic equation
X =0.004693 M
pH = -log[H⁺]
pH = - log [ 0.004693 ]
pH = 2.3285
Hope that helps!
Answer:
So a sodium atom has the electronic configuration 2,8,1 meaning it has 1 electron on its outer shell. It has a neutral charge since the number of electrons is equal to the number of protons.
A sodium ion is one that has lost the electron on its valence shell. The electronic configuration is 2,8 and it has a positive charge because it has more protons than electrons.