All categories

4 years ago

How many atoms are accommodated by the available orbitals for Ne?

Chemistry

1 answer:

PIT_PIT [208]4 years ago

3 0

The relative atomic mass of Ne = 20.2. Therefore 20.2 g of neon contains 6.022 × 1023 Ne atoms.

You might be interested in

A sample of a gas occupies 2.76 L at 303K. What would the volume be if the temperature was increased to 404K? Assume constant

Artist 52 [7]

Answer:

If the temperature was increased to 404 K, its volume would be 3.68 L.

Explanation:

Charles' Law gives a relationship between the volume and the temperature of the gas at constant temperature. This law states that the volume of a given amount of gas held at constant pressure is directly proportional to the temperature.

$V\propto T$

$\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$

Let

$V_1=2.76\ L\\\\T_1=303\ K\\\\T_2=404\ K$

Let $V_2$ is new volume. Using above formula we get :

$V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{2.76\times 404}{303}\\\\V_2=3.68\ L$

If the temperature was increased to 404 K, its volume would be 3.68 L.

6 0

4 years ago

Convert 3.2 moles of ch4 to number of molecules

REY [17]

Answer: 1.93 x 10^24 molecules

Explanation:

CH4 is the chemical formula for methane, the first member of the alkane family.

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 molecule

So, 1 mole of CH4 = 6.02 x 10^23 molecules

3.2 moles of CH4 = Z

To get the value of Z, cross multiply:

(Z x 1 mole) = (6.02 x 10^23 molecule x 3.2 moles)

Z•mole = 19.26 x 10^23 molecules•mole

Divide both sides by 1 mole

Z•mole / 1 mole = 19.26 x 10^23 molecules•mole/ 1mole

Z = 19.26 x 10^23 molecules

Place Z in standard form

Z = 1.93 x 10^24 molecules

Thus, 3.2 moles of ch4 has 1.93 x 10^24 molecules

3 0

4 years ago

If the sun rises at 7:36am and sets at 6:00pm, what times would we use for our data in the 24-hour clock format?

Dmitrij [34]

C is the answer I used to work at McDonald’s I know military time

6 0

3 years ago

If 44.7 g of KCI (MM = 74.55 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the

navik [9.2K]

1.199 M is the concentration of KCI in the resulting solution.

<h3 /><h3>What are moles?</h3>

A mole is defined as 6.02214076 × $10^{23}$ of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

No.of moles of KCI

$Moles = \frac{mass}{molar \;mass}$

$Moles = \frac{44.7 g}{74.5513 g/mol}$

= 0.599 moles

Vol.of the solution,V= 500 ml

= 0.5 liter

Molarity

$Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}$

$Molality = \frac{0.599 moles}{0.5 liter}$

= 1.199 M

Hence, 1.199 M is the concentration of KCI in the resulting solution.

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

6 0

3 years ago

Using the balanced equation N2+O2=2NO, how many grams of NO can be produced when 25.0 grams of N react?

Oxana [17]

Answer:

$53.55gNO$

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible for us to calculate the produced grams of nitrogen monoxide by starting with 25.0 g of nitrogen via their 1:2 mole ratio and the molar masses of 30.1 g/mol and 28.02 g/mol, respectively and by some stoichiometry:

$=25.0gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNO}{1molN_2}*\frac{30.01 gNO}{1molNO}\\\\=53.55gNO$

Best regards!

8 0

3 years ago