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3 years ago

How many atoms are accommodated by the available orbitals for Ne?

Chemistry

1 answer:

PIT_PIT [208]3 years ago

3 0

The relative atomic mass of Ne = 20.2. Therefore 20.2 g of neon contains 6.022 × 1023 Ne atoms.

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an, 13 Students set up two environments see which one best supports growth of hibiscus flowers. One environment is created as a

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B. The Enviroment. The Soil and Humidity are differant. They both have high tematures, they use the same flowers in both, Hibiscus. The tropical environent should help the Hiviscus grow better.

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3 years ago

What is the nature of the SE-CI bond in molecule of selenium chloride ( SeCI3) if the electronegativity value of selenium is 2.5

blondinia [14]

3.2-2.5 = 0.7 pretty small difference

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3 years ago

Calculate the acid dissociation constant of a weak monoprotic acid if a 0.5M solution of this acid gives a hydrogen-ion concentr

RUDIKE [14]

Let the acid be HA.
The chemical formula for this acid will be the following:

$HA \rightleftharpoons H^{+}+A^{-}$

The formula for the acid dissociation constant will be the following:

 $K_a= \dfrac{[H^+][A^-]}{[HA]}$

We know [H+]=0.0001 (it's given).
However, we must find [A-] and [HA] in order to solve for the constant.

We find that [A-]=[H+] by using a electroneutrality equation.
Also, we can create a concentration equation to find [HA].

 $0.5M=[A^-]+[HA]$
$[HA]=0.5M-[A^-]$

Now, we can find the acid dissociation constant.

 $K_a= \dfrac{[H^+][A^-]}{0.5M-[A^-]}$

$= \dfrac{0.0001*0.0001}{0.5-0.0001} = 2.0*10^{-8}$

4 0

3 years ago

The statement "matter can be neither created nor destroyed by chemical means, but it can be changed from one form to another" is

Tatiana [17]

your answer is b. conservation of matter.

i just took the test

8 0

3 years ago

Read 2 more answers

an iron bar weighed 664 g. after the bar had been standing in moist air for a month, exactly one-eighth of the iron turned to ru

DaniilM [7]

The final mass of the iron bar and the rust when the weight of the bar was 664g and the bar had been standing in moist air for a month, will be 688.456g.

One-eighth of the iron bar turns to rust, which means the mass of the iron bar that has undergone rusting= 664/8= 83g

Thus, the mass of pure iron left after rusting has taken place will be= (664-83)g= 581g.

The equation of rusting is as follows

4Fe + 3O2 + 6H2O → 4Fe(OH)3

Molecular weight of iron is 55.84g, thus iron will undergo the reaction= 83/55.84= 1.486 mole

Mass of Fe2O3= 159.68g

4 moles of iron produce 4 moles of rust or iron oxide

Thus, 1.486 mole of iron will produce 1.486 mole iron oxide

Mass of iron oxide= 159.68/ 1.486

Mass of rust = 107.456g

Therefore, mass of iron bar= (581+ 107.456)g

= 688.456g

To learn more about rusting, click

brainly.com/question/18376414

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2 years ago