Answer:
Explanation:
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cheers i hope this helps
Given:
size of scale model = 4(size of pump)
power ratio of pump and scale model = 5:1
Solution:
Let the diameter of scale model and pump be
and
respectively
and head be
and
respectively
Now, power, P is given as a function of head(H) and dischagre(Q)
P =
(1)
From eqn (1):

and

So,

Therefore,
= 
= 
= 
= 
= 
Answer:
Define the problem
I hope this helps!
Explanation:
The problem must be know before you can develop and solution, generate concepts, or construct and test a prototype
Answer:
stone wheel
Explanation:
it was built around 3500 B.C.
Answer:
a) the flow under full capacity is q₂= 1.334 ft³/s
b) the velocity would be v= 3.793 ft/s
Explanation:
a) Since the pipe has 8 inches in diameter but 4 are covered with water flow ( half of a circle in area=A₁) , q₁=0.662 ft³/s then
q₁=A₁*v
then for the same velocity v but area A₂=2*A₁
flow under full capacity= q₂ = A₂*v= 2*A₁*v= 2*q₁=2*0.662 ft³/s= 1.334 ft³/s
b) when flowing at a depth of 4 inches
A₁= (1/2)*(π*D²/4) = π* (1/8)*(8 in)² = 8π in² * (1 ft²/ 144 in²) = π/18 ft² = 0.1745 ft²
then
v=q₁/A₁ = 0.662 ft³/s/0.1745 ft²= 3.793 ft/s
v= 3.793 ft/s