I would go with C but i am not 100 percent on that
Answer:
<em> - 14.943 W/m^2K ( negative sign indicates cooling ) </em>
Explanation:
Given data:
Area of FPC = 4 m^2
temp of water = 60°C
flow rate = 0.06 l/s
ambient temperature = 8°C
exit temperature = 49°C
<u>Calculate the overall heat loss coefficient </u>
Note : heat lost by water = heat loss through convection
m*Cp*dT = h*A * ( T - To )
∴ dT / T - To = h*A / m*Cp ( integrate the relation )
In (
) = h* 4 / ( 0.06 * 10^-3 * 1000 * 4180 )
In ( 41 / 52 ) = 0.0159*h
hence h = - 0.2376 / 0.0159
= - 14.943 W/m^2K ( heat loss coefficient )
Answer:
The shear plane angle and shear strain are 28.21° and 2.155 respectively.
Explanation:
(a)
Orthogonal cutting is the cutting process in which cutting direction or cutting velocity is perpendicular to the cutting edge of the part surface.
Given:
Rake angle is 12°.
Chip thickness before cut is 0.32 mm.
Chip thickness is 0.65 mm.
Calculation:
Step1
Chip reduction ratio is calculated as follows:


r = 0.4923
Step2
Shear angle is calculated as follows:

Here,
is shear plane angle, r is chip reduction ratio and
is rake angle.
Substitute all the values in the above equation as follows:




Thus, the shear plane angle is 28.21°.
(b)
Step3
Shears train is calculated as follows:


.
Thus, the shear strain rate is 2.155.