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Furkat [3]
3 years ago
5

A certain volume of a gas had a pressure of 800 torr at a temperature of -40 degrees C. What was the original volume if the volu

me at STP is now 450.0 cm^3?
(the correct answer is 365 cm^3. I just need an explanation.)
Chemistry
1 answer:
nikitadnepr [17]3 years ago
8 0

Answer : The original volume of gas is 365cm^3

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 800 torr

P_2 = final pressure of gas at STP = 760 torr

V_1 = initial volume of gas = ?

V_2 = final volume of gas at STP = 450.0cm^3

T_1 = initial temperature of gas = -40^oC=273+(-40) =233K

T_2 = final temperature of gas at STP = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

\frac{800torr\times V_1}{233K}=\frac{760torr\times 450.0cm^3}{273K}

V_1= 364.8cm^3\approx 365cm^3

Therefore, the original volume of gas is 365cm^3

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Answer:

The answer to the question is;

The equilibrium constant for the reaction is 0.278

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Explanation:

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The kind of reaction is a reversible one as the equilibrium constant is greater than 0.01 which as general guide, all components in a reaction with an equilibrium constant between the ranges of 0.01 and 100 will be present when equilibrium is reached and the chemical reaction will be reversible.

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