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natita [175]
2 years ago
12

PH is a logarithmic scale used to indicate the hydrogen ion concentration, [H+], of a solution: pH=−log[H+] Due to the autoioniz

ation of water, in any aqueous solution, the hydrogen ion concentration and the hydroxide ion concentration, [OH−], are related to each other by the Kw of water: Kw=[H+][OH−]=1.00×10−14 where 1.00×10−14 is the value at approximately 297 K. Based on this relation, the pH and pOH are also related to each other as 14.00=pH+pOH.
The temperature for each solution is carried out at approximately 297 K where Kw=1.00×10−14.

a. 0.40 g of hydrogen chloride (HCl) is dissolved in water to make 4.5 L of solution. What is the pH of the resulting hydrochloric acid solution?
b. 0.80 g of sodium hydroxide (NaOH) pellets are dissolved in water to make 2.0 L of solution. What is the pH of this solution?
Chemistry
1 answer:
umka21 [38]2 years ago
7 0

Answer:

a. 2.6

b. 12.0

Explanation:

a.

First, we will calculate the molar concentration of HCl.

M = mass of HCl / molar mass of HCl × liters of solution

M = 0.40 g / 36.46 g/mol × 4.5 L

M = 2.4 × 10⁻³ M

HCl is a strong monoprotic acid, so [H⁺] = 2.4 × 10⁻³ M. The pH is:

pH = -log [H⁺]

pH = -log 2.4 × 10⁻³ = 2.6

b.

First, we will calculate the molar concentration of NaOH.

M = mass of NaOH / molar mass of NaOH × liters of solution

M = 0.80 g / 40.00 g/mol × 2.0 L

M = 0.010 M

NaOH is a strong base with 1 OH⁻, so [OH⁻] = 0.010 M. The pOH is:

pOH = -log [OH⁻]

pOH = -log 0.010 = 2.0

The pH is:

14.00 = pH + pOH

pH = 14.00 - pOH = 14.00 - 2.0 = 12.0

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It converts the electrical entertainment into thermal energy, (heat energy) which heats the toast.
6 0
3 years ago
Which of the following are correct for zero-order reactions?
GREYUIT [131]

Answer:

The answer is "Choice A and Choice B"

Explanation:

The Zero-Order reactions are usually found if a substrate, like a surface or even a catalyst, is penetrated also by reactants. Its success rate doesn't depend mostly on the amounts of the various reaction in this reaction.

Let the Rate = k

As \frac{dx}{dt} \ rate\ \  K_0 doesn't depend on reaction rate, a higher reaction rate does not intensify the reaction.

By the rate k_0 =\frac{dx}{dt}, the created based and the reaction rate is about the same.

5 0
2 years ago
A metal ion Mⁿ⁺ has a single electron. The highest energy line in its emission spectrum occurs at a frequency of 2.961 x 10¹⁶ Hz
Whitepunk [10]

Answer:

z≅3

Atomic number is 3, So ion is Lithium ion (Li^+)

Explanation:

First of all

v=f*λ

In our case v=c

c=f*λ

λ=c/f

where:

c is the speed of light

f is the frequency

\lambda=\frac{3*10^8}{2.961*10^{16}}\\ \lambda=1.01317*10^{-8} m

Using Rydberg's Formula:

\frac{1}{\lambda}=R*z^2*(\frac{1}{n_1^2}-\frac{1}{n_2^2})

Where:

R is Rydberg constant=1.097*10^7

z is atomic Number

For highest Energy:

n_1=1

n_2=∞

\frac{1}{1.01317*10^{-8}}=1.097*10^{7}*z^2*(\frac{1}{1^2}-\frac{1}{\inf})\\z^2=8.99\\z=2.99

z≅3

Atomic number is 3, So ion is Lithium ion (Li^+)

3 0
3 years ago
How many moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm?
marshall27 [118]

Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is  021.65 mole

Mole is the unit of amount of substances of specified elementary entities

According to the ideal gas law he number of moles of a gas n can be calculated knowing the partial pressure of a gas p in a container with a volume V at an absolute temperature T from the equation

n =pV/RT

Here given data is volume = 87.1 liters

Temperature = 74 °C means 347.15 k

Pressure = 3.5 atm

R = 0.0821

Putting this value in ideal gas equation then

n =pV/RT

n =  3.5 atm×87.1 liters / 0.0821 ×347.15 k

n = 021.65 mole

Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is  021.65 mole

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8 0
8 months ago
In this salt water floating egg experiment, how will you use these calculations to find the density of the egg? I’m really confu
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Glass 1 Freshwater  

The egg went directly to the base of the glass. Consequently it has sunk and did not drift  

237.0  

237 (1 glass)  

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Glass 2  

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A similar outcome for glass 2 as container 1 when egg was set into the container it sank to the base.  

248.4  

237  

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Glass 3  

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In reference to glass 1 and 2 the egg sank to the base for a third time.  

254.1  

237  

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Glass 4  

Water with 4 teaspoons of salt  

The egg remained gliding to where a little bit of the egg was standing out on the top, and when pushed down the egg returned up.  

259.8  

237  

1.096

Hope this helps!

5 0
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