Answer is: <span>he boiling point of a 1.5 m aqueous solution of fructose is </span>100.7725°C.
The boiling point
elevation is directly proportional to the molality of the solution
according to the equation: ΔTb = Kb · b.<span>
ΔTb - the boiling point
elevation.
Kb - the ebullioscopic
constant. of water.
b - molality of the solution.
Kb = 0.515</span>°C/m.
b = 1.5 m.
ΔTb = 0.515°C/m · 1.5 m.
ΔTb = 0.7725°C.
Tb(solution) = Tb(water) + ΔTb.
Tb(solution) = 100°C + 0.7725°C = 100.7725°C.
Answer:
Situation B indicates the significant depression of temperature in the wet bulb thermometer.
Answer Statement: B
Explanation:
Temperature Depression & Relative Humidity
As we can see that there are four cases to study the affect of relative humidity on the temperature measured by thermometers, set up in different situations i.e., one is dry and the other one is dry.
As situation B describes the most admissible temperature drop in the wet bulb thermometer with a relative humidity of approximately 17% i.e., this can be the appropriate to reflect the lowest relative humidity with a fact that the relative humidity reduces with a larger count of temperature depression. Whereas, the relative humidity for other situations are resulting much higher.
I believe it occurs along the plates edge.
Yo sup??
number of protons=number of electrons =8
but this is the condition when the molecule is neutral
since it has a +3 charge now therefore no of electron is
=8-3
=5
The correct answer is option B
Hope this helps
