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SOVA2 [1]
3 years ago
5

Take a beaker (jar or jug) with some water and put some drops of red or blue ink in it.Take a tender twig of any flowery plant w

ith leaves and flowers ,preferably white flowers,and put it in the beaker for 6 to 8 hours. What do you observe?For further examination cut across its stem and look for the presence of coloured water.Explain your observations.
Chemistry
1 answer:
frutty [35]3 years ago
8 0

Answer:

After about 6 to 8 hours, the white flowers begins to develop red spots near the edge of the petals.

When the stems were cut, coloured water was observed along the length of the stem.

Explanation:

In the experiment, red ink was placed in the beaker of water and a red-coloured water was obtained. Then the tender twig of a flowery plant (e.g. carnation) with leaves and white flowers was placed in the beaker. After about 6 to 8 hours, the white flowers began to develop red spots near the edge of the petals. When the stems were cut, coloured water was observed along the length of the stem. The observations in this experiment is due to the fact that the stem conducted the water and the ink through the xylem up to the leaves. On getting to the leaves, the water evaporates from the leaves in a process known as transpiration leaving behind the red ink. This ink then appears as the red spots on the leaves.

The process of transpiration in the leaves results in the continuous conduction of water from the stem to leaves, and hence, the appearance of more coloured spots with time.

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Consider the reaction: CH4 + 2O2 = CO2 + 2H2O
crimeas [40]

Answer:

The answer to your question is:

a)  80 g of O2

b) O2, 15.13 g of CO2

c) It's not posible to know which is the limiting reactant.

Explanation:

Reaction                             CH4   +   2O2   ⇒   CO2   +   2H2O

a. Calculate the grams of O2 needed to react with 20.00 grams of CH4. _____________

MW CH4 = 16 g

MW O2 = 32 g

                               16 g of CH4 ----------------  2(32) g of O2

                               20 g              --------------    x

                               x = (20 x 64) / 16 = 80 g of O2

b. Given 15.00 g. of CH4 and 22.00 g. of O2, identify the limiting reactant and calculate the grams of CO2 that can be produced. LR _________ grams CO2 _________ .  

                                CH4   +   2O2   ⇒   CO2   +   2H2O

                                15 g         22 g

                                16 g of CH4 ----------------  64 g of O2

                                15 g of CH4  ---------------   x

                               x = (15 x 64) / 16 = 60 g of O2

The Limiting reactant is O2 because it is necessary 60g of O2 for 16 g of CH4 and there are only 22.

                                 CH4   +   2O2   ⇒   CO2   +   2H2O

                        64 g of O2 ------------------  44 g of CO2

                        22 g of O2 ------------------   x

                        x = (22 x 44)/ 64 = 15. 13 g of CO2

c. For the reaction CH4 + 2O2 = CO2 + 2H2O, if you have 10.31 g. of CH4 and an unknown amount of oxygen, and form 20.00 g. of CO2, i. Identify if there is a limiting reactant ______________ ii. Calculate the number of grams of the limiting reactant present if there is one. ______________  

                           CH4   +   2O2   ⇒   CO2   +   2H2O                              

                           10.31 g                     20 g

We can identify the limiting reactant if we know the quantity of the reactants, if we only know the quantity of one it is not posible to which is the limiting reactant.

4 0
3 years ago
A substance that is ______ will NOT dissolve in a solvent. A) freezing B) insoluble C) evaporating D) soluble
Alexxandr [17]

Answer:

insoluble

Explanation:

4 0
3 years ago
Read 2 more answers
What do all the elements in one row of the periodic table have in common?
Hoochie [10]

Answer:

B

Explanation:

This is because the periodic table is designed this way.

5 0
3 years ago
Read 2 more answers
You have 8 moles of a gas at 250 K in a 6 L container. What is the pressure of the gas? Show your work
Bogdan [553]

Hello:

In this case, we will use the Clapeyron equation:

P = ?

n = 8 moles

T = 250 K

R = 0.082 atm.L/mol.K

V = 6 L

Therefore:

P * V = n *  R * T

P * 6 = 8 * 0.082* 250

P* 6 = 164

P = 164 / 6

P = 27.33 atm


Hope that helps!

7 0
3 years ago
PLEASE HELP ASAP PLEASE
USPshnik [31]

Answer:

<em>If it served you, give me 5 stars please, thank you!</em>

<em />

<em>m = </em><u><em>25</em></u><em> </em><em> </em><u><em>Kg</em></u>

8 0
3 years ago
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