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SOVA2 [1]
2 years ago
5

Take a beaker (jar or jug) with some water and put some drops of red or blue ink in it.Take a tender twig of any flowery plant w

ith leaves and flowers ,preferably white flowers,and put it in the beaker for 6 to 8 hours. What do you observe?For further examination cut across its stem and look for the presence of coloured water.Explain your observations.
Chemistry
1 answer:
frutty [35]2 years ago
8 0

Answer:

After about 6 to 8 hours, the white flowers begins to develop red spots near the edge of the petals.

When the stems were cut, coloured water was observed along the length of the stem.

Explanation:

In the experiment, red ink was placed in the beaker of water and a red-coloured water was obtained. Then the tender twig of a flowery plant (e.g. carnation) with leaves and white flowers was placed in the beaker. After about 6 to 8 hours, the white flowers began to develop red spots near the edge of the petals. When the stems were cut, coloured water was observed along the length of the stem. The observations in this experiment is due to the fact that the stem conducted the water and the ink through the xylem up to the leaves. On getting to the leaves, the water evaporates from the leaves in a process known as transpiration leaving behind the red ink. This ink then appears as the red spots on the leaves.

The process of transpiration in the leaves results in the continuous conduction of water from the stem to leaves, and hence, the appearance of more coloured spots with time.

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One hundred million copper atoms are arranged in a line. Which is a reasonable estimate for the length of this line?
Anettt [7]
The size of an atom is roughly 10^-10 metres

10^-10 • 100,000,000 = 0.01 metres

Since 1 metre = 100 centimetre

0.01 x 100 = 1 centimetre

There’s your answer
8 0
3 years ago
One main difference between a Prokaryotic cell and an Eukaryotic cells is __________.
sasho [114]
The Eukaryotic cell has a nucleus
8 0
2 years ago
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Positive Deviation from Raoult's Law occurs when the vapour pressure of component is greater than what is expected in Raoult's L
8090 [49]

Answer:

All of the above.

Explanation:

In positive deviation from Raoult's  Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.

When a solution is non ideal then it shows positive or negative deviation.

Let two solutions A and B to form non- ideal solutions.let the vapour pressure  of component A is P_A and vapour pressure of component B is P_B.

P^0_A= Vapour pressure of component A in pure form

P^0_B= Vapour pressure of component B in pure form

x_A=Mole fraction of component A

x_B==Mole fraction of component B

The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.

P_A >P^0_A\cdot x_A,P_B>P^0_B\cdot x_B

Therefore, P_A+P_B >P^0_A\cdot x_A+P^0_B \cdot x_B

Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.

Hence, option a,b,c and d are true.

6 0
3 years ago
Which types of electron orbitals will have higher energy than a 4d orbital?
alexdok [17]

Answer:

D) 4f

Explanation:

To determine which electron orbital that will have higher energy than a 4d orbital, we write the electron configuration starting with s-orbital.

1s

2s         2p

3s         3p          3d       3f

4s         4p          4d       4f

5s         5p           5d       5f

6s         6p          6d       6f

7s         7p           7d       7f

In ascending order, 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 3f, <u>4d</u><em>,</em> 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 6f, 7d, 7f.

From the electronic configuration formula above, the electron orbitals that have higher energy than a 4d orbital are 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 6f, 7d, 7f.

Therefore, 4f is the correct answer.

8 0
2 years ago
What is the difference between stable and unstable isotopes
Alja [10]

Answer:

stable isotopes have stable nuclei and do not show radioactivity, but for unstable isotopes it is the opposite

Explanation:

hope this helps, ask more questions if needed.

6 0
3 years ago
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