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SOVA2 [1]
2 years ago
5

Take a beaker (jar or jug) with some water and put some drops of red or blue ink in it.Take a tender twig of any flowery plant w

ith leaves and flowers ,preferably white flowers,and put it in the beaker for 6 to 8 hours. What do you observe?For further examination cut across its stem and look for the presence of coloured water.Explain your observations.
Chemistry
1 answer:
frutty [35]2 years ago
8 0

Answer:

After about 6 to 8 hours, the white flowers begins to develop red spots near the edge of the petals.

When the stems were cut, coloured water was observed along the length of the stem.

Explanation:

In the experiment, red ink was placed in the beaker of water and a red-coloured water was obtained. Then the tender twig of a flowery plant (e.g. carnation) with leaves and white flowers was placed in the beaker. After about 6 to 8 hours, the white flowers began to develop red spots near the edge of the petals. When the stems were cut, coloured water was observed along the length of the stem. The observations in this experiment is due to the fact that the stem conducted the water and the ink through the xylem up to the leaves. On getting to the leaves, the water evaporates from the leaves in a process known as transpiration leaving behind the red ink. This ink then appears as the red spots on the leaves.

The process of transpiration in the leaves results in the continuous conduction of water from the stem to leaves, and hence, the appearance of more coloured spots with time.

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Please help me with chemistry!
Helga [31]

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

Explanation:

Reacting bromide (Br₂) with sodium iodine (NaI) will produce sodium bromide (NaBr) and iodine (I₂).

To balance the equation the number of atoms of each element entering the  reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

where:

l - liquid

s - solid

This is a single replacement reaction because an element in a compound is replaced by another element. Generally a single replacement reaction is represented as: A + BC → AC + B

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types of chemical reactions

brainly.com/question/10105284

balancing chemical equations

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5 0
3 years ago
A mixture of CuSO4 · 5H2O and MgSO4 · 7H2O is heated until all the water is lost. If 5.127 g of the mixture gives 2.817 g of the
Nadusha1986 [10]

Answer:

Let the mixture is X% by mass of CuSO

4

.5H

2

O and 100 - X % by mass of MgSO

4

.7H

2

O. 5.0 g of mixture will contain 0.05X g CuSO

4

.5H

2

O and 5.0 - 0.05X g MgSO

4

.7H

2

O

The molar masses of CuSO

4

.5H

2

O and MgSO

4

.7H

2

O are 249.7 g/mol and 246.5 g/mol respectively.

The number of moles of CuSO

4

.5H

2

O=

249.7

0.05X

=2.00×10

−4

X moles.

Explanation:

Pls mark it as branliest answere thanks

3 0
2 years ago
a technician mixes 80 ml of a 5% solution with 10 ml of water. what is the final percentage strength of the solution prepared?
Vinvika [58]

A technician mixes 80 ml of a 5% solution with 10 ml of water.  the final percentage strength of the solution prepared is 40 %.

given that :

8 ml of a 5 % solution mix with 10 ml . that means the 80 mL of 5 % solution is diluted with water of 10 mL

therefore, 80 × 5 = 10 × x %

x % = 40 %

Therefore, the final percentage strength of the solution is 40 %

Thus, A technician mixes 80 ml of a 5% solution with 10 ml of water.  the final percentage strength of the solution prepared is 40 %.

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brainly.com/question/17130362

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5 0
1 year ago
1. Calculate the RFM of Fe(NO3)2
miss Akunina [59]

Answer:

The Relative Formula Mass of Fe(NO₃)₂ is 179.8524 grams

Explanation:

The Relative Formula Mass is the mass of one mole of a compound expressed in grams, obtained by adding together the Relative Atomic Masses, RAM, of the elements which makes the compound

The Relative Formula Mass of a compound is the same as its Relative Molecular Mass

The relative formula mass of Fe(NO₃)₂ is given as follows;

The relative atomic mass of Fe = 55.845 amu

The relative atomic mass of nitrogen, N = 14.0067 amu

The relative atomic mass of oxygen, O = 15.999 amu

Therefore, we have;

The formula mass of Fe(NO₃)₂ = (55.845 + 2×(14.0067 + 3×15.999)) amu = 179.8524 amu

The Relative Formula Mass of Fe(NO₃)₂ = 179.8524 grams.

5 0
2 years ago
Plz help :(
ziro4ka [17]
<h2>Answer:0.5 moles,1 mole</h2>

Explanation:

Sr(NO_{3})_{2} is readily soluble in water.

Sr(NO_{3})_{2} dissolves in water to give Sr^{2+} ions and NO_{3}^{-} ions.

The reaction is

Sr(NO_{3})_{2}→Sr^{2+}+2NO_{3}^{-}

So,1 mole of Sr(NO_{3})_{2} gives 1 mole of Sr^{2+} and 2 moles of NO_{3}^{-}.

So,0.5 moles of Sr(NO_{3})_{2} gives 0.5 moles of Sr^{2+} and 1 mole of NO_{3}^{-}.

5 0
3 years ago
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