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stepan [7]
3 years ago
11

Kate and Janie are about to pour water into a beaker when they notice

Chemistry
2 answers:
SVETLANKA909090 [29]3 years ago
8 0
They should throw it away and use a different one
storchak [24]3 years ago
4 0

Answer:

Put the beaker in the broken glassware disposal and replace the beaker

Explanation:

Any beaker which has a crack could break/shatter if you apply heat. Also, cracked glassware is a lab safety hazard.

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Why is there a pop sound when a burning splint is extinguished in a test tube filled with hydrogen gas?
AveGali [126]
Hydrogen is actually a combustible gas. But when you try to burn it, it explodes. However when you produce hydrogen in a laboratory, which is relatively less, and put a burning splint, it also explodes, but  in a reduced form - a <span>POP </span><span>sound. The very small explosion (doesn't feel like one, does it?) extinguishes the flame.</span>
7 0
3 years ago
Light waves come in different wavelengths and frequencies. The color of the light we see is dependent on wavelength. When we see
galben [10]
When we see a rainbow, we are actually seeing colors of different wavelengths : mainly, red orange yellow green blue indigo and violet (in descending order of their wavelengths.)
5 0
3 years ago
I have to covert 4.4×10^4 Pa in to atm
Kitty [74]
The answer is 4.40000
5 0
3 years ago
Suppose now that you wanted to determine the density of a small crystal to confirm that it is phosphorus. From the literature, y
denis23 [38]

Answer:

Volume of CHCl_3   = 15.31 mL

Volume of CHBr_3 = 4.69 mL

Explanation:

Given that:

the density of the mixture = 1.82 g/mL

From the density of the pure samples

The density of CHCl_3 = 1.492 g/mL

The density of CHBr_3 = 2.890 g/mL

The total volume of the liquid mixture = 20.0 mL

Suppose the volume of  CHCl_3 = P ml

and the volume of CHBr_3 = Q ml

the sum of their volumes should be equal to the total volume of the mixture

P \ ml + Q \ ml = 20 ml  ----- (1)

However, we know that Density = mass/volume

∴ mass = density × volume

The equation can now be expressed as:

\mathtt{(Density \ of  \ CHCl_3 \times Vol. \ of  \ CHCl_3 ) + (Density  \  of \  CHBr_3  \times \ volume \ of \ CHBr_3)} = \mathtt{ (Density  \ of \ mixture \times volume \ of \ the \ mixture)}

1.492 g/mL × P mL + 2.890 g/mL × Q mL = 1.82 g/mL × 20 mL  ---- (2)

From equation (1) ;

let Q = 20 - P

The replace the value of P into equation (2)

1.492 g/mL × P mL + 2.890g/mL × (20 - P) mL = 1.82 g/mL × 20 mL

1.492 P g + 57.8g - 2.890 P g =  36.4g

1.492 P g - 2.890 P g = 36.4g - 57.8g

-1.398 P g = -21.4g

P = -21.4g/-1.398g

P = 15.31 mL

Q = 20 - P

Q = (20 - 15.31) mL

Q = 4.69 mL

∴

Volume of CHCl_3   = 15.31 mL

Volume of CHBr_3 = 4.69 mL

6 0
3 years ago
Calculate the pH of a solution whose H3O+ concentration is 2.1 x 10-3 M. Is the solution acidc, basic, or neutral?
Leona [35]

Answer:

Option A, The pH of the solution is 2.7 and the solution is acidic

Explanation:

As we know,

pH =  - log [H3O+]

Substituting the given values, we get

pH =  - log [2.1 x 10-3 M]

pH =  - (-2.678)

pH = 2.678 or 2.7

The solution is acidic as pH value is less than 7

Hence, option A is correct

5 0
3 years ago
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