0.012moldm⁻³
Explanation:
Given parameters:
Mass of AgNO₃ = 1000mg
Volume of water = 500mL
Unknown:
Molarity of solution = ?
Solution:
The molarity of a solution is the number of moles of a solute dissolved in volume of solvent.
Molarity = 
Number of moles of AgNO₃ = ?
Number of moles = 
Molar mass of AgNO₃ = 108 + 14 + 3(16) = 170g/mol
convert mass to g;
1000mg = 1g
Number of moles =
= 0.00588moles
convert the given volume to dm³;
1000mL = 1dm³;
500mL = 0.5dm³
Now solve;
Molarity =
= 0.012moldm⁻³
learn more:
Molarity brainly.com/question/9324116
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Answer:Answer: The step that is NOT necessary to complete before a cuvette is placed into the spectrophotometer is option B (Write, in ink, either sample or blank on the side of the cuvette to keep track of them)
Explanation: spectrophotometer is an instrument used to measure the light intensity absorbed after being passed through a solution. Before the absorbance of the sample solution, a solvent solution called blank is used for the calibration of the machine and this blank solvent is placed in a cuvette. The procedure usually comes first before the main sample is processed. Therefore there is no need to
Write, in ink, either sample or blank on the side of the cuvette to keep track of them. This is so since sample and blank is not absorbed at the same time by the machine.
The balanced equation would be 
<h3>Electrochemical equations</h3>
Zn reacts with Cu solution according to the following equation:

In the reaction,
is reduced according to the following: 
While Zn is oxidized according to the following: 
Thus, giving the overall equation of; 
More oxidation-reduction equations can be found here: brainly.com/question/13699873
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Answer:
Following are the solution to these question:
Explanation:
Calculating the mean:


Calculating the standardn:

Please find the correct equation in the attached file.

For point a:

For point b:

For point c:

It is calculated by using the slope value that is
. The slope value
is ambiguous.
Answer:
Nitrogen and Oxygen make up 99% of the Earths atmosphere. Then Argon makes up the rest of the atmosphere.