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cestrela7 [59]
3 years ago
15

How many moles of NO2 are present in 138.01 g

Chemistry
1 answer:
Sophie [7]3 years ago
8 0

Answer:

3.0002 moles

Explanation:

Data Given:

mass of NO₂ = 138.01 g

No. of moles NO₂ = ?

Solution

To find mass of sample mole formula will be used

mole formula

          no. of mole = mass in grams / molar mass

Molar mass of NO₂ = 14 + 2(16)

Molar mass of NO₂ = 14 + 32 = 46 g/mol

Put values in above equation

               no. of mole = 138.01 g / 46 g/mol

               no. of mole = 3.0002 moles

no. of mole of NO₂ = 3.0002 moles

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