Answer:
The answer to your question is 40 L of NH₃
Explanation:
Data
Volume of NH₃ = x
mass of N₂ = 25 g
mass of H₂ = excess
Balanced chemical reaction
N₂ + 3H₂ ⇒ 2NH₃
Process
1.- Find the molar mass of N₂ and NH₃
N₂ = 14 x 2 = 28g
2NH₃ = 2[ 14 + 3] = 34 g
2.- Write a proportion to solve this problem
28 g of N₂ --------------- 34 g of NH₃
25 g of N₂ ------------- x
x = (25 x 34)/28
x = 30.36 g of NH₃
3.- Calculate the volume of NH₃
17 g of NH₃ -------------- 22.4 L
30.36 g of NH₃ -------- x
x = (30.36 x 22.4) / 17
x = 40 L
1cm^3 = 1L would be the correct answer. One cubic centimeter equals .001 liter, so this equality above is not correct.
Please let me know if you have any questions! :)
The volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L (option B).
<h3>How to calculate volume?</h3>
The volume of a substance can be calculated using the following formula:
P1V1 = P2V2
Where;
- P1 = initial pressure
- P2 = final pressure
- V1 = initial volume
- V2 = final volume
153 × 3 = 304 × V2
459 = 304V2
V2 = 459/304
V2 = 1.51L
Therefore, the volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L.
Learn more about volume at: brainly.com/question/2098026
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