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zaharov [31]
3 years ago
9

What is the atomic mass of one mole of H? _______g/mol

Chemistry
1 answer:
Nikolay [14]3 years ago
8 0
The answer is 1.008g/mol
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Calculate how many moles of silver nitrate (AgNO3) are in 1.35 L of a 4.25 M solution of silver
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Answer:

is

Explanation:

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¿En dónde se ubican los lípidos solubles?
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Assign oxidation numbers to the element in each of the following compounds. Remember an oxidation number is for one atom of the
worty [1.4K]

Answer:

a.  x = + 2

b.  x = + 3

c.  x = + 2

d.  x = + 3

Explanation:

The oxidation number is a formal charge assigned to an atom present in a molecule or formula unit or ion based on some arbitrary rules.

a.

<u>Hg</u>O

The oxidation number of Hg in HgO is:

x + (-2) = 0

x = +2

b.

<u>Al₄</u>C₃

The oxidation number of Al in Al<u>₄</u>C₃ is:

4x +(3 × -4) = 0

4x - 12 = 0

4x = +12

x = 12/4

x = +3

c. CrF₂

x + ( 2 × - 1) = 0

x - 2 = 0

x = + 2

d. Fe₂S₃

2x + ( 3 × - 2) = 0

2x + (-6) = 0

2x = 6

x = 6/2

x = +3

7 0
3 years ago
During photosynthesis, plants transform
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A company is testing drinking water and wants to ensure that ca content is below 155 ppm. What is the maximum amount of Ca that
BabaBlast [244]

Answer:

138 mg

Explanation:

A company is testing drinking water and wants to ensure that Ca content is below 155 ppm (= 155 mg/kg), that is, <em>155 milligrams of calcium per kilogram of drinking water</em>. We need to find the maximum amount of calcium in 890 g of drinking water.

Step 1: Convert the mass of drinking water to kilograms.

We will use the relation 1 kg = 1000 g.

890g \times \frac{1kg}{1000g} =0.890kg

Step 2: Calculate the maximum amount of calcium in 0.890 kg of drinking water

0.890gH_2O \times \frac{155mgCa}{1kgH_2O} = 138mgCa

7 0
3 years ago
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