For every 1 molecule of Magnesium hydroxide or Mg(OH)2 there will be 2 molecules of HCl neutralized.
If molar mass of magnesium hydroxide is 58.3197g/mol, the amount of mol in 5.50 g magnesium hydroxide should be: 5.50g/ (<span>58.3197g/mol)= 0.0943mol.
Then, the amount of HCl molecule neutralized would be: 2* </span>0.0943mol= 0.18861 mol
If molar mass of HCl is 36.46094 g/mol, the mass of the molecule would be: 0.18861 mol* 36.46094g/mol = 6.88grams
NH3 has 1 Nitrogen atom and 3 hydrogen atoms.
984 grams of strontium will be recovered from 9.84x10^8 cubic meter of seawater.
Explanation:
From the question data given is :
volume of strontium in sea water= 9.84x10^8 cubic meter
(1 cubic metre = 1000000 ml)
so 9 .84x10^8 cubic meter
= 984 ml.
density of sea water = 1 gram/ml
from the formula mass of strontium can be calculated.
density = 
mass = density x volume
mass = 1 x 984
= 984 grams of strontium will be recovered.
98400 centigram of strontium will be recovered.
Strontium is an alkaline earth metal and is highly reactive.
<span>Atoms with greatly different electronegativity values are expected to form </span>ionic bonds
Answer: The volume of
required is 25.0 ml
Explanation:
According to the neutralization law,
where,
= basicity
= 1
= molarity of
solution = 2.00 M
= volume of
solution = 50.0 ml
= acidity of
= 1
= molarity of
solution = 4.00 M
= volume of
solution = ?
Putting in the values we get:
Therefore, volume of
required is 25.0 ml