Before the bullet is fired the momentum is Zero because nothing is moving but once the bullet is shot the momentum increases because of the movement of the bullet moving forward.
Answer:
![\large \boxed{\text{44.5 mL}}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5Ctext%7B44.5%20mL%7D%7D)
Explanation:
When adding or subtracting values, you must round your answer to the same "place" as the measurement with its last significant figure furthest to the left.
That is, you round off to the same number of decimal places as the measurement with the fewest decimal places.
![\begin{array}{r|r}19.9& \text{3 mL}\\14.0&\text{mL}\\10.6&\text{mL} \\\mathbf{44.5} &\textbf{3 mL}\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Br%7Cr%7D19.9%26%20%5Ctext%7B3%20mL%7D%5C%5C14.0%26%5Ctext%7BmL%7D%5C%5C10.6%26%5Ctext%7BmL%7D%20%5C%5C%5Cmathbf%7B44.5%7D%20%26%5Ctextbf%7B3%20mL%7D%5C%5C%5Cend%7Barray%7D)
The measurements of 14.0 and 10.6 have one digit after the decimal point, so you round the sum to have only one digit to the right of the decimal.
The number to be dropped (3) is less than 5, so you drop it.
![\text{The total volume of the three beakers is $\large \boxed{\textbf{44.5 mL}}$}](https://tex.z-dn.net/?f=%5Ctext%7BThe%20total%20volume%20of%20the%20three%20beakers%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B44.5%20mL%7D%7D%24%7D)
Old but good do a volcano <span />
Answer: Object B will heat up more.
Explanation:
The formula for specific heat is as follows.
Q = ![m C \Delta T](https://tex.z-dn.net/?f=m%20C%20%5CDelta%20T)
Where,
Q = heat provided
m = mass
C = specific heat
= change in temperature
Now, both the objects have same mass and equal amount of heat is applied.
According to the formula, the equation will be as follows.
= ![Q_{2}](https://tex.z-dn.net/?f=Q_%7B2%7D)
= ![m C_{2}\Delta T_{2}](https://tex.z-dn.net/?f=m%20C_%7B2%7D%5CDelta%20T_%7B2%7D)
Cancel m from both sides, as mass is same. Therefore,
= ![C_{2}(T_{f} - T_{i})_B](https://tex.z-dn.net/?f=C_%7B2%7D%28T_%7Bf%7D%20-%20T_%7Bi%7D%29_B)
Cancel out the initial temperature and put the values of specific heat, then the equation will be as follows.
= ![0.82(T_{f})_B](https://tex.z-dn.net/?f=0.82%28T_%7Bf%7D%29_B)
Therefore, from the above equation it can be concluded that the object with low specific heat will heat up more as its specific heat will be inversely proportional to its final temperature.
Hence, object B will heat up more.