Help pleeb, I'm not an imbecile I'm just to lazy to do the work myself. will give brainliest.
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Answer : The correct answer is New concentration = 0.125 M and final volume = 0.150 M
Given :
Molarity of NaCl solution = 0.150 M volume of NaCL solution = 125 mL
Volume of water added = 25 mL
1) Final volume = ? 2) New concentration = ?
1) To find the final volume :
New volume = volume of NaCl solution + volume of water added
= 125 mL + 25 mL
= 150 mL
Converting this final volume from mL to L
1 L = 1000 mL
Final volume = 0.150 L
2) To find new concentration :
Following steps can be used :
a) To find mole of NaCl :
Mole of NaCl can be calculated using molarity formula . Molarity can be defined as mole of solute present in Liter of solution (volume ) .It represents Concentration of solution . It used unit as M or . It can be expressed as :
Molarity of NaCl solution = 0.150
Volume of NaCl solution = 0.125 mL or 0.125 L
Plugging these values in molarity formula
Multiplying both side by 0.125 L
Mole of NaCl = 0.01875 mol
b) To find New concentration :
Since the mole of NaCl remians same when water is added . Hence new concentration ( molarity )can be calculated using mole of NaCl and final volume .
Mole of NaCL = 0.01875 mol
Final volume = 0.150 L
plugging values in molarity formula :
New concentration = 0.125 M