Answer : The hydrocarbons containing a saturated carbon ring are called Aliphatic cyclic hydrocarbon.
Explanation :
As the organic compounds are classified into two categories that is acyclic (aliphatic) and cyclic (aromatic) compounds.
Acyclic compounds : It is an open chain compound with linear structure.
Cyclic compounds : It is a closed chain compound having a carbon ring structure.
Hydrocarbon : It is an organic compound that contains only hydrogen and the carbon atoms. They are of two types which are saturated hydrocarbon and unsaturated hydrocarbon.
Saturated hydrocarbon : These are the compounds which containing single bonds between the carbon-carbon atoms. In saturated compounds, there are more number of hydrogen bonded with the carbon atom.
Unsaturated hydrocarbon : These are the compounds which containing double and triple bonds between the carbon-carbon atoms. In unsaturated compounds, there are less number of hydrogen bonded with the carbon atom.
Hence, the hydrocarbons containing a saturated carbon ring are called Aliphatic cyclic hydrocarbon.
Answer:
the answer is static friction.
It is the third one this is simple
![\LARGE{ \boxed{ \rm{ \red{Required \: answer}}}}](https://tex.z-dn.net/?f=%20%5CLARGE%7B%20%5Cboxed%7B%20%20%5Crm%7B%20%5Cred%7BRequired%20%5C%3A%20answer%7D%7D%7D%7D)
☃️ Chemical formulae ➝ ![\sf{CaCO_3}](https://tex.z-dn.net/?f=%5Csf%7BCaCO_3%7D)
<h3>
<u>How to find?</u></h3>
For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.
![\boxed{ \sf{No. \: of \: moles = \frac{given \: weight}{molecular \: weight} }}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Csf%7BNo.%20%5C%3A%20of%20%5C%3A%20moles%20%3D%20%20%5Cfrac%7Bgiven%20%5C%3A%20weight%7D%7Bmolecular%20%5C%3A%20weight%7D%20%7D%7D)
<h3>
<u>Solution:</u></h3>
Atomic weight of elements:
Ca = 40
C = 12
O = 16
❍ Molecular weight of ![\sf{CaCO_3}](https://tex.z-dn.net/?f=%5Csf%7BCaCO_3%7D)
= 40 + 12 + 3 × 16
= 52 + 48
= 100 g/mol
❍ Given weight: 10 g
Then, no. of moles,
⇛ No. of moles = 10 g / 100 g mol‐¹
⇛ No. of moles = 0.1 moles
☄ No. of moles of Calcium carbonate in that substance = <u>0.1 moles</u>
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Answer:
Cu + 2AgNo3 is the reactants