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Mariana [72]
3 years ago
14

How many moles of AgNO3 are present in 1.50 L of a 0.050 M solution?

Chemistry
2 answers:
elixir [45]3 years ago
8 0
To calculate the moles of AgNO3 in a solution, we need to know the volume and concentration of the solution. 
Moles of AgNO3 = Volume of AgNO3 solution (L) * concentration of AgNO3 solution (M or mole/L) = 1.50 L * 0.050 M = 0.075 mole.

So 0.075 moles of AgNO3 are present in 1.50 L of a 0.050 M solution.
Lisa [10]3 years ago
4 0

Answer: 0.075 Moles of AgNO3.

Explanation:

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A 32.8 g sample of gas occupies 22.414 L at STP. What is the molecular weight of this gas?
olasank [31]

Answer:

32.8g/mole

Explanation:

Given parameters:

Mass of sample of gas = 32.8g

Volume  = 22.4L

Unknown:

Molecular weight  = ?

Solution:

To solve this problem we must understand that at rtp;

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Number of mole of the gas  = 1 mole

 Now;

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8 0
3 years ago
2FeCl3 ---> 2FeCl2 + Cl2
vesna_86 [32]
The correct options are as follows: 
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2. In the reaction given above, the chlorine atom is OXIDIZED.
An oxidation is a process in which an atom loses an electron, thereby increasing its oxidation number. In this case, the positive character of the atom is increased. Looking at the chlorine atom given above, you will notice that it has a charge of -1 before and now it has change to neutral, which means that, it has given out the electron it gains earlier.

3. This type of redox reaction can not take place. This is because, in chemical reaction, the chlorine atom is always looking for another element that will donate an electron to it in order to become stable. Thus, chlorine atom easily gain electrons but it can not donate an electron to another element.<span />
8 0
3 years ago
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sineoko [7]
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3 years ago
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worty [1.4K]

Answer:

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Explanation:

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