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Anon25 [30]
2 years ago
14

What data do you need to determine the specific heat capacity of a substance?

Chemistry
1 answer:
strojnjashka [21]2 years ago
6 0

Speific heat capacity is measured with the aid of determining how a whole lot warmth electricity is needed to increase one gram of a substance one digree Celsius. The Speific heat capacity of water is 4.2 joules per gram per degree Celsius or 1 calorie in step with gram per digree Celsius.

The specific heat capacity is defined as the amount of heat (J) absorbed consistent with unit mass (kg) of the substance while its temperature increases 1 ok (or 1 °C), and its units are J/(kg k) or J/(kg °C).

Factors specific heat capacity relate to are temperature and strength.

The Speific heat capacity C can be measured as q = mC∆T

Or, C = q/m∆T

where,

C is the specific heat capacity

q is the quantity of heat required

m is the mass

∆T is the change in temperature

As a consequence so as to degree the specific heat capacity we need to recognize mass of the substance, quantity of heat lost or gain by the substance and the exchange in temperature.

Lear more about Speific heat capacity here: brainly.com/question/17162473

#SPJ4

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If you had a bottle that contained 5.69x1024 molecules of water, how many
Valentin [98]
Yeah what the other person said ^
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3 years ago
A compound is found to contain 37.32 % phosphorus , 16.88 % nitrogen , and 45.79 % fluorine by
Alla [95]

Answer: 1. The empirical formula is PNF_2  

2. The molecular formula is PNF_2

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of P = 37.32 g

Mass of N = 16.88 g

Mass of F = 45.79 g

Step 1 : convert given masses into moles.

Moles of P =\frac{\text{ given mass of P}}{\text{ molar mass of P}}= \frac{37.32g}{31g/mole}=1.20moles

Moles of N =\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{16.88g}{14g/mole}=1.20moles

Moles of F =\frac{\text{ given mass of F}}{\text{ molar mass of F}}= \frac{45.79g}{19g/mole}=2.41moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For P = \frac{1.20}{1.20}=1

For N = \frac{1.20}{1.20}=1

For F =\frac{2.41}{1.20}=2

The ratio of P: N: F= 1: 1: 2  

Hence the empirical formula is PNF_2

The empirical weight of PNF_2= 1(31)+1(14)+2(19)= 82.98 g.

The molecular weight = 82.98 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{82.98}{82.98}=1

The molecular formula will be=1\times PNF_2=PNF_2

3 0
3 years ago
PLEASE HELP I WILL FAIL Which level of organization in the classification system is directly above the genus level? Domain Famil
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Above the Genus is the classification level called Family. Plz mark me Brainliest if I'm right.
4 0
3 years ago
Read 2 more answers
One mole of any gas at 298K and one ATM occupies a volume of 222.4 L. True or false
emmainna [20.7K]

Answer:

The answer is... TRUE!!

Explanation:

I hope i helped you! =)

6 0
4 years ago
Suppose 45.0 g of water at 85 °C is added to 105.0 g of ice at 0 °C. The molar heat of fusion of water is 6.01 kJ/mol, and the s
Elis [28]

Answer:

A. Final Temp = 36.428C and

47.9g ice will melt

Explanation:

Given the following data:

Mass of water (M1) = 45.0g = 0.045kg

Temperature (T1) = 85C = 358k

Mass of ice (M2) = 105g = 0.105kg

Temperature (T2) = 0c = 273k

Specific heat of water (C) = 4.18j/gC = 0.00418kj/kgc

Molar heat of fusion of water = 6.01kj/mol

Therefore, heat required (q) = MCT

M1C(T1-T2) = M2C∆T

By putting the data we have

0.045×0.00418×(358-273) = 0.105×0.00418×∆T

∆t = 0.045×0.00418×85/0.105×0.00418

∆t = 36.428C

Gram of ice that would melt would be 47.9g

4 0
3 years ago
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