Answer:
The theoretical yield of Cu(s) in moles is 60.15 moles
Explanation:
Step 1: Data given
Number of moles CuO = 70.8 moles
Number of moles NH3 = 40.1 moles
Molar mass CuO = 79.545 g/mol
Molar mass NH3 = 17.03 g/mol
Step 2: The balanced equation
3CuO(s) + 2NH3(g) → 3H2O(l) + 3Cu(s) + N2(g)
For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2
NH3 is the limiting reactant. It will completely be consumed (40.1 moles). CuO is in excess. There will react 3/2 * 40.1 = 60.15 moles
There will remain 70.8 - 60.15 = 10.65 moles CuO
Step 3: Calculate moles Cu
For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2
For 40.1 moles NH3 we'll have 60.15 moles Cu
The theoretical yield of Cu(s) in moles is 60.15 moles
Answer:
0.84kg of gatorade powder
Explanation:
From the question given, we were told that 0.6kg of gatorade powder required 5 gallons of water.
To obtain the mass of gatorade needed for 7 gallons of water, we simply do the following:
0.6kg of gatorade powder required 5 gallons of water.
Therefore, xkg of gatorade powder will require 7 gallons of water i.e
xkg of gatorade powder = (0.6 x 7)/5
xkg of gatorade powder = 0.84kg
Therefore, 0.84kg of gatorade powder will be required.
First and foremost, they are completely different substances with each exhibiting unique properties. Both have different atoms involved on their structures which is the cause of the differing properties.
