Answer:
8. Convection
9. Heat (Radiation)
10. Between -210 and -196
11. Vacuum
12. Infrared
13. Convection
14. Unit Joule or British thermal unit and calorie are used too
15. (I don't understand what's being asked here)
Hope this Helps you
Did 1-7 need answers? or no?
The muzzle speed is 144 m/s.
Let x = the angle of elevation.
Then
u = 144 cos(x), the horizontal velocity
v = 144 sin(x), the vertical launch velocity
Assume no air resistance, and g = 9.8 m/s².
To hit the target 780 m away, the time of flight is
t = (780 m)/[144 cos(x)] = 5.4167 sec(x) s
In terms of the vertical velocity,
(144 sin(x) m/s)*(5.4167 sec(x) s) + (1/2)*(-9.8 m/s²)*(5.4167 sec(x) m/s)² = (780 m)
780 tan(x) - 143.769 sec²x = 780
tan(x) - 0.1843 (1 + tan²x) = 1
0.1843 tan²(x) - tan(x) + 1.1843 = 0
tan²x - 5.4259 tan(x) + 6.4259 = 0
Solve with the quadratic formula.
tan(x) = 0.5[5.4259 +/- √(3.737)] = 3.6795 or 1.7464
x = tan⁻¹ 3.6795 = 74.8°
or
x = tan⁻¹ 1.7464 = 60.2°
Answer: (74.8°, 60.2°)
Answer:D-550 N
Explanation:
Given
mass of student=50 kg
at particular instant elevator is moving downward with acceleration of 1 m/s^2
Net weight of man shown by scale will be more than his actual weight as elevator is decelerating
let N be the normal reaction on man thus
and Normal reaction will be shown by scale as apparent weight
The Greeks thought that the sun was the center of the Univesre for plantets like earth to observe it !!!
Answer:
Thus, the change in the weight of the person is 1.6N , option c is correct.
Explanation: