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ASHA 777 [7]
3 years ago
14

1 AI A3 If A1 = 27A and A3 = 1.9A, what would A2 read?

Physics
1 answer:
Gnoma [55]3 years ago
7 0

Answer:

0.8A

Explanation:

because im very intelligent and beautiful so the answer is correct and its 0.8A

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Explanation:

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An unknown source plays a pitch of middle C (262 Hz). How fast would the sound wave from this source have to travel to raise
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Answer:

The sound travels at v_{s}=11.4 \mathrm{m} / \mathrm{s}

Option: c

Explanation:

Unknown source plays of middle C (fs) = 262 Hz

The sound wave from this source have to travel to raise the pitch to C sharp is (fd) = 272 Hz

\begin{array}{l}{velocity of sound in air(v)=343 \mathrm{m} / \mathrm{s}, f_{\mathrm{s}}=262 \mathrm{Hz}, f_{\mathrm{d}}=271 \mathrm{Hz}} \\ {velocity of receiver(v_{\mathrm{d}})=0 \mathrm{m} / \mathrm{s},velocity of source( v_{\mathrm{s}}) \text { is unknown }}\end{array}

\text { Speed of sound } \mathrm{V}_{\mathrm{S}}=343 \mathrm{m} / \mathrm{s}

f_{\mathrm{d}}=f_{\mathrm{s}}\left(\frac{v-v_{\mathrm{d}}}{v-v_{\mathrm{s}}}\right)

\frac{f_{d}}{f_{s}}=\left(\frac{v-v_{d}}{v-v_{s}}\right)

\left(v-v_{s}\right)=\frac{f_{s}}{f_{d}}\left(v-v_{d}\right)

v_{s}=v-\frac{f_{s}}{f_{d}}\left(v-v_{d}\right)

Substitute the given values in the formula,

v_{s}=343+\frac{262}{271}(343-0)

v_{s}=343+0.966(343)

v_{s}=343-331.33

v_{s}=11.4 \mathrm{m} / \mathrm{s}

Therefore, The sound travels at v_{s}=11.4 \mathrm{m} / \mathrm{s}

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This means the amount of energy an electromagnetic wave carries depends on its wavelength (or its frequency), because the speed of light and h are constant.

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