Answer:
We have that Assuming No air resistance,the initial horizontal velocity of the cannonball is
From the question we are told that
A cannonball is shot from a cannon at a launch angle of 35 and an initial velocity of 147 m/s
Generally the equation for the horizontal velocity is mathematically given as
Therefore
Therefore Assuming No air resistance,the initial horizontal velocity of the cannonball is For more information on this visit
Explanation:
Yes glass is an insulator
Answer:
a) Total distance travelled = 1.9km + 8.7km + 3.0km = 13.6km
b) Total displacement = -1.9km + 8.7km-3.0km=+3.8km
Total displacement = 3.8km due west
Explanation:
a) Total distance travelled is a scalar quantity it is not affected by the direction it's only concerned with the magnitude.
Total distance travelled = 1.9km + 8.7km + 3.0km = 13.6km
b) Total displacement is a vector quantity it takes into consideration both magnitude and direction.
Taking west as positive and east as negative.
Total displacement = -1.9km + 8.7km-3.0km = +3.8km
Total displacement = 3.8km due west
The answer is C. An occluded front.
The angle between the transmission axes of the polarizers if it is desired that one-tenth of the incident intensity be transmitted, ∝ = 63.435°
We'll assume that 
represents the incident light's intensity. Two polarizers are provided to us, but the first polarizer's angle is not disclosed. The incident light in situations like this needs to be unpolarized. This is due to the fact that, regardless of angle, the transmitted intensity via the polarizer is reduced by half for unpolarized light:
Then,
By using Malu's law,
That is,
In terms of , we get
Now the angle is,
cos ∝ = 0.44721
Then, ∝ = 63.435°
This angle is measured with respect to the first polarizer angle.
Learn more about the polarizers here: brainly.com/question/13008007
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