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meriva
3 years ago
7

Question 4 - If Angelica starts out at 30m/s, and in 16 s speeds up to 84 m/s, what is her acceleration?

Physics
1 answer:
Triss [41]3 years ago
4 0

Answer:

C. 3.375 m/s^2

Explanation:

The acceleration of an object can be found using the equation:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time it takes for the velocity to change from u to v

In this problem:

u = 30 m/s is the initial velocity of Angelica

v = 84 m/s is the final velocity

t is the time

Substituting into the equation, we find the acceleration:

a=\frac{84-30}{16}=3.375 m/s^2

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<u>Explanation</u>:

As per given question,

m_{1} \text { is } 140 \mathrm{kg}

m_{2} \text { is } 160 \mathrm{kg}

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Where,

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\text { G is the Universal Gravitational Constant }=6.674 \times 10^{-11} \mathrm{N}-\mathrm{m}^{2} / \mathrm{kg}^{2}

m_{1} \text { and } m_{2} \text { are the masses of the two objects in kilograms (kg) }

R is the separation in meters (m) between the objects

Substitute the given values in the above formula,

F=\frac{6.674 \times 10^{-11} \times 140 \times 160}{0.895^{2}}

F=\frac{1.494 \times 10^{-6}}{0.801}

\mathrm{F}=1.865 \times 10^{-6}

\text { The force between the given two objects is } 1.865 \times 10^{-6} \mathrm{N}

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3 years ago
Every atom contains a<br> .............. which is positively charged
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Explanation:

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dybincka [34]

Answer:

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Explanation:

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