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inn [45]
3 years ago
7

What has more mass, a mole of sodium chloride or 2 moles of aluminum?

Chemistry
1 answer:
eimsori [14]3 years ago
5 0

Answer:

2 moles of aluminum

Explanation:

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Pla helppp due in 5 minutes!!..
Doss [256]
G o o g le (particle arrangements for solids) etc itll give you good images and just draw them in !
8 0
3 years ago
Student A is pulling 57 newtons and student B is pushing at 96 newtons. What is the net force?
Elis [28]

Answer:

153 N left

Hope this helps

Explanation:

8 0
3 years ago
What is the change in temperature in a 128g sample of titanium if it absorbs 2808J of heat energy at a temperature of 2°C? The s
Katena32 [7]

Given:

128g sample of titanium

2808J of heat energy

specific heat of titanium is 0.523 J/ g °C.

Required:

Change in temperature

Solution:

This can be solved through the equation H = mCpT where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.

Plugging in the values into the equation

H = mCpT

2808J = (128g) (0.523 J /g °C) T

T = 41.9 °C

3 0
3 years ago
Intact cells of two unknown cell types were placed into solutions with different concentrations of NaCl. Type I cells swelled an
Bess [88]

Answer:

Cell Type I: Animal cell surrounded by a plasma membrane only.

Cell Type II: Plant cell surrounded by a plasma membrane and a cell wall.

Explanation:

Hello,

In this case, we must remember that animal cells are covered only by a plasma membrane, which is not enough to keep the cell from bursting as no limit for the inlet salt is established, causing it both to swell and burst. On the other hand, plant cells are covered by both a plasma membrane and a cell wall which contributive effect allow the inlet of the salt but prevent the cell to burst as the cell wall is rigid. In such a way, based on the described situation, one infers that the cell type I is an animal cell surrounded by a plasma membrane only the cell type II is a plant cell surrounded by a plasma membrane and a cell wall.

Best regards.

3 0
3 years ago
What is the theoretical yield of vanadium, in moles, that can be produced by the reaction of 1.0 mole of V2O5 with 4.0 moles of
IRINA_888 [86]

Answer:

Theoretical yield of vanadium = 1.6 moles

Explanation:

Moles of V_2O_5 = 1.0 moles

Moles of Ca = 4.0 moles

According to the given reaction:-

V_2O_5_{(s)} + 5Ca_{(l)}\rightarrow 2V_{(l)} + 5CaO_{(s)}

1 mole of V_2O_5 react with 5 moles of Ca

Moles of Ca available = 4.0 moles

Limiting reagent is the one which is present in small amount. Thus, Ca is limiting reagent. (4.0 < 5)

The formation of the product is governed by the limiting reagent. So,

5 moles of Ca on reaction forms 2 moles of V

1 mole of Ca on reaction for 2/5 mole of V

4.0 mole of Ca on reaction for \frac{2}{5}\times 4 mole of V

Moles of V = 1.6 moles

<u>Theoretical yield of vanadium = 1.6 moles</u>

4 0
3 years ago
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