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vivado [14]
3 years ago
12

How many liters of oxygen are required to react completely with 14.8 mol of Al?

Chemistry
1 answer:
Bond [772]3 years ago
8 0

Answer:

296 L  

Explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

                  4Al + 3O₂ ⟶ 2Al₂O₃

n/mol:        17.4

1. Moles of O₂

n = \text{17.4 mol Al}\times \dfrac{\text{3 mol O}_{2}}{\text{4 mol Al}}= \text{13.05 mol O}_{2}

2. Volume of O₂

You haven't given the conditions at which the volume is measured, so I assume it is at STP (0 °C and 1 bar).

At STP the molar volume of a gas is 22.71 L.

V = \text{13.05 mol}\times \dfrac{\text{22.71 L}}{\text{1 mol }}= \textbf{296 L}

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The oxidation of copper(I) oxide, Cu2O(s) , to copper(II) oxide, CuO(s) , is an exothermic process. 2Cu2O(s)+O2(g)⟶4CuO(s) The c
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The work is  

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The energy  change of the reaction is  \Delta U _{rxn} = 43.839 kJ  

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From the question we are told that

    The chemical equation for this reaction is

             2 Cu_2 O + O_2_{(g)} ----> 4 CuO_{(s)}

     The mass of  Cu_2 O is  m = 42.60g

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        n = \frac{mass \ of   \ Cu_2 O}{Molar \ mass \  of   \ Cu_2 O}

The molar mass of Cu_2 O is  a constant with a value  M = 143.1 g/mol

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             n = \frac{ 42.60}{143.1}

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From the reaction we see that

Two mole of Cu_2 O  reacts with One mole of O_2 to give Four moles of  CuO_{(s)}

This means that

One mole of  Cu_2 O  reacts with 0.5 mole of O_2 to give two moles of  CuO_{(s)}

it also implies that

0.29769 \ mole of  Cu_2 O  reacts with 0.5 * 0.29769 moles of O_2 to give 2* 0.29769 moles of  CuO_{(s)}

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0.29769 \ mole of  Cu_2 O  reacts with 0.149 moles of O_2 to give 0.595 moles of  CuO_{(s)}

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      N_{O_2} = 0.149 \ moles

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         \Delta N = 0- 0.149 \ moles

        \Delta N = - 0.149 \ moles

Now the workdone for  the compound Cu_2 O is mathematically represented as

        W = \Delta N RT

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     Substituting values

     W = -0.149 * 8.314 * (298)

     W = -0.369kJ

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           \Delta U _{rxn} = \Delta H_{re} - W

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        \Delta U _{rxn} = 43.839 kJ  

This is the internal energy change on the reaction for 42.60 g of Cu_2 O

       

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