How many liters of oxygen are required to react completely with 14.8 mol of Al?
1 answer:
Answer:
296 L
Explanation:
We will need a balanced equation with moles, so let's gather all the information in one place.
4Al + 3O₂ ⟶ 2Al₂O₃
n/mol: 17.4
1. Moles of O₂
2. Volume of O₂
You haven't given the conditions at which the volume is measured, so I assume it is at STP (0 °C and 1 bar).
At STP the molar volume of a gas is 22.71 L.
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Answer:
The work is
The energy change of the reaction is
Explanation:
From the question we are told that
The chemical equation for this reaction is
The mass of is
The enthalpy is
this also the change in energy in terms of heat
The pressure at which it is oxidized is
The no of moles of used in this reaction is mathematically represented as
The molar mass of is a constant with a value
Now substituting values
From the reaction we see that
Two mole of reacts with One mole of
to give Four moles of
This means that
One mole of reacts with 0.5 mole of
to give two moles of
it also implies that
of
reacts with
moles of
to give
moles of
so
of
reacts with
moles of
to give
moles of
Now the number of moles of gaseous reactant is
The number of moles of gaseous product is
So the change in number of moles for gaseous compounds is mathematically evaluated as
Now the workdone for the compound is mathematically represented as
Where R is the gas constant with a value of
T is the temperature with a value
Substituting values
Generally the internal energy change of the reaction can be represented as
Substituting value
This is the internal energy change on the reaction for 42.60 g of