Answer:
(a) 43.2 kC
(b) 0.012V kWh
(c) 0.108V cents
Explanation:
<u>Given:</u>
- i = current flow = 3 A
- t = time interval for which the current flow =
- V = terminal voltage of the battery
- R = rate of energy = 9 cents/kWh
<u>Assume:</u>
- Q = charge transported as a result of charging
- E = energy expended
- C = cost of charging
Part (a):
We know that the charge flow rate is the electric current flow through a wire.
Hence, 43.2 kC of charge is transported as a result of charging.
Part (b):
We know the electrical energy dissipated due to current flow across a voltage drop for a time interval is given by:
Hence, 0.012V kWh is expended in charging the battery.
Part (c):
We know that the energy cost is equal to the product of energy expended and the rate of energy.
Hence, 0.108V cents is the charging cost of the battery.
I'm quite certain the answer is "stress".
Answer: 20m/s.
Explanation:
Remember the second Newton's law:
F = a*m
This is:
The net force acting on an object is equal to the mass of the object times the acceleration of the object.
In this case, we have a force of 5N pushing the object to the right.
We also have a force of 5N pushing the object to the left.
These forces act on opposite directions.
Then the net force will be equal to the difference of these forces, this is:
F = 5N - 5N = 0N
Then the net force is 0N, then we have:
0N = m*a
0N/m = 0m/s^2 = a
This means that the acceleration of the object is 0, then the velocity of the object does not change.
This means that if the object was moving at a constant velocity of 20m/s, the velocity of the object will still be equal to 20m/s. (because the net force acting on the object is zero)
Answer:
45000 Kg.m/s
Explanation:
change in momentum = m( v¹-vi)
=3000(25-10)
= 45000
