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cupoosta [38]
3 years ago
14

HELP WILL MARK BRAINLIEST

Physics
1 answer:
zvonat [6]3 years ago
6 0

Answer is D

Explanation:

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A Ping-Pong ball has a mass of 2.3 g and a terminal speed of 9.4 m/s. The drag force is of the form bv^2 What is the value of b?
julia-pushkina [17]
Drag Force = bv^2 = ma; a = g = 9.81 m/s^2

b = mg/v^2 = (0.0023×9.81)/(9.4^2)

b = 0.000255


6 0
3 years ago
At what rate does gravity cause objects to accelerate at sea level on earth
VLD [36.1K]

The acceleration due to gravity on Earth is 9.8 m/s per second.

5 0
3 years ago
you push a sled of mass 15 kg across the snow with a force of 180 N for a distance of 2.5 m. There is no friction. if the sled s
Oxana [17]
<span>7.7 m/s First, determine the acceleration you subject the sled to. You have a mass of 15 kg being subjected to a force of 180 N, so 180 N / 15 kg = 180 (kg m)/s^2 / 15 kg = 12 m/s^2 Now determine how long you pushed it. For constant acceleration the equation is d = 0.5 A T^2 Substitute the known values getting, 2.5 m = 0.5 12 m/s^2 T^2 2.5 m = 6 m/s^2 T^2 Solve for T 2.5 m = 6 m/s^2 T^2 0.41667 s^2 = T^2 0.645497224 s = T Now to get the velocity, multiply the time by the acceleration, giving 0.645497224 s * 12 m/s^2 = 7.745966692 m/s After rounding to 2 significant figures, you get 7.7 m/s</span>
5 0
3 years ago
A woman is standing in the ocean, and she notices that after a wavecrest passes, five more crests pass in a time of 50.0 s. Thed
Vadim26 [7]

Answer:

(a) T = 10 s

(b) f = 0.1 Hz

(c) λ = 32 m

(d) v = 3.2 m/s

(e) Insufficient data

Explanation:

(a)

Time period is defined as the time interval required for one wave to pass. Therefore, the time period can be given as:

T = Period = Time Taken/No. of Waves

T = 50 s/5

<u>T = 10 s</u>

<u></u>

(b)

Frequency is the reciprocal of time period:

f = frequency = 1/T

f = 1/10 s

<u>f = 0.1 Hz</u>

<u></u>

(c)

Wavelength is the distance between two consecutive crests or troughs:

<u>λ = Wavelength = 32 m</u>

<u></u>

(d)

Speed of wave is given by the following formula:

Speed = v = fλ

v = (0.1 Hz)(32 m)

v = 3.2 m/s

(e)

Amplitude cannot be found with given data.

6 0
3 years ago
A blue car pulls away from a red stop-light just after it has turned green with a constant acceleration of 0.2 m/s2. A green car
jolli1 [7]

Answer:

After 15 seconds, the green car will catch up with the blue car

Explanation:

Let the time for the green car to catch up with the blue car be T

When the green car catches up to the blue car, the distances covered by each car after time T will be equal. Also, their velocities at that instant will be equal

Distance covered by blue car after time T is given by: s = ut + 0.5 at²

Where u = 0, a = 0.2 m/s², t = T

S = 0.5 × 0.2 × T² = 0.1 T²

Velocity of blue car, v = u+ at

v = 0.2T

Distance covered by green car at T is given as: S = Velocity × time

Where v = 0.2T, t = T - 7.5 (since the blue car started 7.5 seconds earlier)

S = 0.2T (T - 7.5)

S = 0.2 T² - 1.5T

Equating the distance covered by the two cars

0.2T² - 1.5T = 0.1T²

0.1T² - 1.5T = 0

T(0.1T - 1.5) = 0

T = 0 or

T = 1.5/0.1 = 15 secs

Therefore, after 15 seconds, the green car will catch up with the blue car

8 0
2 years ago
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