One horsepower (1 hp) is the unit of power based on the work that a horse can do in one second. This is defined, in English unit
1 answer:
Power is defined as rate of work done which means it is work done in 1 second of time
Now it is given that we have a horse that will give power 745.7 W
So it will do work of 745.7 J in 1 second of time
now if we wish to find the work done by horse in 0.55 s
so we can say
So it will do total work of 410.14 J in 0.55 s of time
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The distance from the horizontal top surface of the cube to the water level is "6.282 cm".
<h3>What is Archimedes' principle?</h3>According to Archimedes' principle, the weight of the fluid that the body displaces is equal to the upward buoyant force that is applied to a body submerged in a fluid, whether fully or partially. The Archimedes' principle is a fundamental physical law in fluid mechanics. It was created by Syracuse's Archimedes.
According to Archimedes' principle, a body submerged in a fluid experiences an upward force proportional to the weight of the fluid that has been displaced. One of the prerequisites for equilibrium is this. We believe that the buoyancy force, also known as the centre of buoyancy, is situated in the middle of the submerged hull.
From Archimedes' principle, we get
=11.72cm
So,
The distance from horizontal top to the water level will be:
=18-11.72
=6.282cm
To learn more about Archimedes' principle refer to:
#SPJ4
These are actually 4 different exercises:
ex 1) The sailboat moves north, while the wind moves from southeast. This means the angle between the direction of the boat and the wind is
.
Calling F the force of the wind, and
the distance covered by the boat, the work done by the wind is:
The total time of the motion is
and therefore the power of the wind is
ex 2) First of all, let's calculate the length of the ramp. Given the two sizes 2.00 m and 6.00 m, we have
The mechanical advantage (MA) of the ramp is the ratio between the output load (W) and the input force (F). The output load is the weight of the load, mg, therefore:
Finally, the efficiency
of the ramp is the ratio between the output energy and the work done. The output energy is simply the potential energy (Ep) of the load, which is mgh, where h is the height of the ramp. The work done W is the product between the input force, F, and the displacement of the load, which is the length of the ramp: Fd. Therefore:
ex 3) the graph is missing
ex 4) We know that the power is the ratio between the work done W and the time t:
But we can rewrite the work as
where F is the force applied, d the displacement of rock and![\theta=60^{\circ]](https://tex.z-dn.net/?f=%5Ctheta%3D60%5E%7B%5Ccirc%5D)
is the angle between the direction of the force and the displacement (3 m).
Therefore we can rewrite the power as
where
is the velocity, Using the data of the exercise, we can then find the force, F:
and now we can also calculate the work, which is
ex 1) The sailboat moves north, while the wind moves from southeast. This means the angle between the direction of the boat and the wind is
Calling F the force of the wind, and
The total time of the motion is
ex 2) First of all, let's calculate the length of the ramp. Given the two sizes 2.00 m and 6.00 m, we have
The mechanical advantage (MA) of the ramp is the ratio between the output load (W) and the input force (F). The output load is the weight of the load, mg, therefore:
Finally, the efficiency
ex 3) the graph is missing
ex 4) We know that the power is the ratio between the work done W and the time t:
But we can rewrite the work as
where F is the force applied, d the displacement of rock and
Therefore we can rewrite the power as
where
and now we can also calculate the work, which is