All categories

2 years ago

5. A.63kg ball is moving at 4.3 m/s. What is the momentum of the ball?

Physics

1 answer:

ziro4ka [17]2 years ago

4 0

->p= mv
->p= 63kg*4.3m/s
->p=270.9 Kgm/s

You might be interested in

Sound waves are mechanical waves. Which statement is true for this type of wave?

Bad White [126]

Answer:

Electromagnetic waves do not require a medium in order to transport their energy. Mechanical waves are waves that require a medium in order to transport their energy from one location to another. ... Sound is a mechanical wave and cannot travel through a vacuum.

6 0

2 years ago

The mass of the sun is 1.9891030 kg and the mass of the Earth is 5.9721024kg. If the Earth’s acceleration toward the sun is 0.00

saul85 [17]

Answer:

this is the answer according to my calculations

Explanation:

0.001.9

5 0

2 years ago

The table below shows the approximate distances of two stars from Earth.

Gemiola [76]

I think that the answer is c. good luck

6 0

3 years ago

While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find th

san4es73 [151]

Answer:

a. $v=3.03\frac{m}{s}$

b. $a_c=0.71\frac{m}{s^2}$

c. $\frac{W_{top}}{W}=0.93$

d. $\frac{W_{bot}}{W}=1.07$

Explanation:

a. The speed is the distance travelled divided by the time:

$v=\frac{2\pi r}{T}\\v=\frac{2\pi(13m)}{27s}\\v=3.03\frac{m}{s}$

b. The magnitud of the centripetal acceleration is given by:

$a_c=\frac{v^2}{r}\\a_c=\frac{(3.03\frac{m}{s})^2}{13m}\\a_c=0.71\frac{m}{s^2}$

c. According to Newton's second law, at the top we have:

$\sum F_{top}:W-W_{top}=ma_c\\W_{top}=mg-ma_c\\W_{top}=m(g-a_c)\\W_{top}=m(9.8\frac{m}{s^2}-0.71\frac{m}{s^2})\\W_{top}=m(9.09\frac{m}{s^2})\\\frac{W_{top}}{W}=\frac{m(9.09\frac{m}{s^2})}{m(9.8\frac{m}{s^2})}\\\frac{W_{top}}{W}=0.93$

d. According to Newton's second law, at the bottom we have:

$\sum F_{bot}:-W+W_{bot}=ma_c\\W_{bot}=mg+ma_c\\W_{bot}=m(g+a_c)\\W_{bot}=m(9.8\frac{m}{s^2}+0.71\frac{m}{s^2})\\W_{bot}=m(10.51\frac{m}{s^2})\\\frac{W_{bot}}{W}=\frac{m(10.51\frac{m}{s^2})}{m(9.8\frac{m}{s^2})}\\\frac{W_{bot}}{W}=1.07$

3 0

3 years ago

An object's gravitational potential energy is directly related to all of the following EXCEPT

LuckyWell [14K]

C, because Ep = m*g*h, so it means it doesn't depends on the object's speed, only its mass, gravity, and height

8 0

3 years ago