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patriot [66]
3 years ago
11

7) The acceleration of gravity on the Moon is only one-sixth of that on Earth. If you hit a baseball on the Moon with the same e

ffort (and at the speed and angle) that you would on Earth, the ball would land 7) _______ A) one-sixth as far. B) the same distance away. C) 6 times as far. D) 36 times as far.
Physics
1 answer:
rusak2 [61]3 years ago
4 0

Answer:

The acceleration of gravity on the Moon is only one-sixth of that on Earth. If we hit a baseball on the moon with the same effort(and at the speed and angle)that we would on earth, the ball would land 6 times as far. The ball on the moon will cover 6 times more distance than Earth.

Explanation:

Speed=distance travelled/Time required speed

Speed=d/t

Acceleration of gravity on earth=9.8 m/s^2

Acceleration of gravity on Moon=1.62 m/s^2

So the maximum height of ball will be the ration of these both gravity.

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As waves get closer to a beach they _____.
krok68 [10]

Answer:

Increase in energy

Explanation:

4 0
3 years ago
An object is moving along a straight line, and the uncertainty in its position is 1.90 m.
just olya [345]

Answer:

2.78\times 10^{-35}\ \text{kg m/s}

6.178\times 10^{-34}\ \text{m/s}

0.31\times 10^{-4}\ \text{m/s}

Explanation:

\Delta x = Uncertainty in position = 1.9 m

\Delta p = Uncertainty in momentum

h = Planck's constant = 6.626\times 10^{-34}\ \text{Js}

m = Mass of object

From Heisenberg's uncertainty principle we know

\Delta x\Delta p\geq \dfrac{h}{4\pi}\\\Rightarrow \Delta p\geq \dfrac{h}{4\pi\Delta x}\\\Rightarrow \Delta p\geq \dfrac{6.626\times 10^{-34}}{4\pi\times 1.9}\\\Rightarrow \Delta p\geq 2.78\times 10^{-35}\ \text{kg m/s}

The minimum uncertainty in the momentum of the object is 2.78\times 10^{-35}\ \text{kg m/s}

Golf ball minimum uncertainty in the momentum of the object

m=0.045\ \text{kg}

Uncertainty in velocity is given by

\Delta p\geq m\Delta v\geq 2.78\times 10^{-35}\\\Rightarrow \Delta v\geq \dfrac{2.78\times 10^{-35}}{m}\\\Rightarrow \Delta v\geq \dfrac{2.78\times 10^{-35}}{0.045}\\\Rightarrow \Delta v\geq 6.178\times 10^{-34}\ \text{m/s}

The minimum uncertainty in the object's velocity is 6.178\times 10^{-34}\ \text{m/s}

Electron

m=9.11\times 10^{-31}\ \text{kg}

\Delta v\geq \dfrac{\Delta p}{m}\\\Rightarrow \Delta v\geq \dfrac{2.78\times 10^{-35}}{9.11\times 10^{-31}}\\\Rightarrow \Delta v\geq 0.31\times 10^{-4}\ \text{m/s}

The minimum uncertainty in the object's velocity is 0.31\times 10^{-4}\ \text{m/s}.

6 0
3 years ago
How is temperature related to the physical change of a<br>substance​
blagie [28]

Answer:

~~Now, you have left your question very open ended and didn't ask for any particular kind of answer so I'll do my best to get what you're looking for.~~

A physical change in a substance doesn't change what the substance is. It can possibly melt or freeze an object. I mean heat makes things expand while cooling makes them retract.... In chemical change where there is a chemical reaction, a new substance is formed and energy is either given off or absorbed.

4 0
4 years ago
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What is the length of 0.005 mm in kilometers?
ZanzabumX [31]
The answer would be 5*10^9&#10;.

If we divide \frac{5*10^9}{1*10^6}, it gives us 0.005!

Hope this helped! c:
4 0
4 years ago
Calculate the total distance traveled (in m)
nlexa [21]

Answer:

Distance is 13m and Displacement is 9m

Explanation:

3 0
4 years ago
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