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dimulka [17.4K]
3 years ago
7

Help plzzzzzzzzzzzzzzzz!

Physics
1 answer:
aksik [14]3 years ago
3 0
 

concave <span>ray diagrams were constructed in order to determine the general location, size, orientation, and type of image formed by concave mirrors. Perhaps you noticed that there is a definite relationship between the image characteristics and the location where an object placed in front of a concave mirror. but, convex</span><span>ray diagrams were constructed in order to determine the location, size, orientation, and type of image formed by concave mirrors. The ray diagram constructed earlier for a convex mirror revealed that the image of the object was virtual, upright, reduced in size and located behind the mirror. </span>
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How long does it take neptune to rotate on its axis
Phoenix [80]
Roughly about seven hundred days
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Which has more momentum, a car traveling at 12 km/h or a bicycle traveling at the same speed ? Explain why
Verizon [17]
The momentum of an object varies directly with the speed of the object. Two objects of different mass are moving at the same speed; the more massive object will have the greatest momentum. A less massive object can never have more momentum than a more massive object.
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Which are ways of showing probability? Check all that apply.
nikitadnepr [17]

i would say

-50%

-3/4

-25%

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8 0
3 years ago
A 6 kg block is released from rest at the top of an incline, as shown above, and slides to the bottom. The incline is 1.97 m lon
viva [34]

The net force on the block acting perpendicular to the incline is

∑ <em>F</em> = <em>n</em> - <em>w</em> cos(29.4°) = 0

where <em>n</em> is the magnitude of the normal force and <em>w</em> = <em>m g</em> is the weight of the block.

The equation itself comes from splitting up the forces acting on the block into components pointing parallel or perpendicular to the incline. The only forces acting on the block in the perpendicular direction are the normal force and the perpendicular component of the block's weight.

Solve for <em>n</em> :

<em>n</em> = <em>m g</em> cos(29.4°)

<em>n</em> = (6 kg) (9.80 m/s²) cos(29.4°)

<em>n</em> ≈ 51.2 N

4 0
3 years ago
"A proton is placed in a uniform electric field of 2750 N/C. You may want to review (Page) . For related problem-solving tips an
tekilochka [14]

To solve this problem we will start from the definition of Force, as the product between the electric field and the proton charge. Once the force is found, it will be possible to apply Newton's second law, and find the proton acceleration, knowing its mass. Finally, through the linear motion kinematic equation we will find the speed of the proton.

PART A ) For the electrostatic force we have that is equal to

F=qE

Here

q= Charge

E = Electric Force

F=(1.6*10^{-19}C)(2750N/C)

F = 4.4*10^{-16}N

PART B) Rearrange the expression F=ma for the acceleration

a = \frac{F}{m}

Here,

a = Acceleration

F = Force

m = Mass

Replacing,

a = \frac{4.4*10^{-16}N}{1.67*10^{-27}kg}

a = 2.635*10^{11}m/s^2

PART C) Acceleration can be described as the speed change in an instant of time,

a = \frac{v_f-v_i}{t}

There is not v_i then

a = \frac{v_f}{t}

Rearranging to find the velocity,

v_f = at

v_f = (2.635*10^{11})(1.4*10^{-6})

v_f = 3.689*10^{5}m/s

7 0
3 years ago
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