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Brums [2.3K]
3 years ago
13

Einstein and Lorentz, being avid tennis players, play a fast-paced game on a court where they stand 20.0 m from each other. Bein

g very skilled players, they play without a net. The tennis ball has mass 0.0580 kg. You can ignore gravity and assume that the ball travels parallel to the ground as it travels between the two players. Unless otherwise specified, all measurements are made by the two men. (a) Lorentz serves the ball at 80.0 m>s. What is the ball’s kinetic energy? (b) Einstein slams a return at 1.80 * 108 m>s. What is the ball’s kinetic energy? (c) During Einstein’s return of the ball in part (a), a white rabbit runs beside the court in the direction from Einstein to Lorentz. The rabbit has a speed of 2.20 * 108 m>s relative to the two men. What is the speed of the rabbit relative to the ball? (d) What does the rabbit measure as the distance from Einstein to Lorentz? (e) How much time does it take for the rabbit to run 20.0 m, according to the players? (f) The white rabbit carries a pocket watch. He uses this watch to measure the time (as he sees it) for the distance from Einstein to Lorentz to pass by under him. What time does he measure?

Physics
1 answer:
igor_vitrenko [27]3 years ago
3 0

Answer:

A) 185.6 J

B) 9.396 x 10^14 J

C) 4x10^7 m/s

D) 20 m

E) 9.09x10^-8 sec

F) 9.09x10^-8 sec

Explanation:

Detailed explanation and calculation is shown in the image below

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Three identical train cars, coupled together are rolling east at 2.0 m/s. A fourth car traveling east at 4.0 m/s catches up with
Ann [662]

Answer:

The value is  v  =  2 \ m/s

Explanation:

From the question we are told that

   The velocity of the each of the three cars is u_1 = u_2 = u_3 =  2 \  m/s

    The velocity of the fourth car is  u_4 =  4 \ m/s

    The initial velocity of the fifth car u_5 =  0 \ m/s

Generally from the law of momentum conservation we have that

    m_1 u_1 + m_2 u_2 + m_3 u_3 +m_4u_4 + m_5u_5 =  [m_1   + m_2 + m_3 +m_4+ m_5]v

Given that the cars are identical then their mass will be the same

i.e

    m_1 =m_2 = m_3 = m_4 = m_5 =  m

=>   [u_1 + u_2 +  u_3 +u_4 + u_5]m =  5mv

=>   2+ 2 +  2 +4 + 0 =  5v

= >   v  =  2 \ m/s

8 0
3 years ago
Imagine that the satellite described in the problem introduction is used to transmit television signals. You have a satellite TV
denpristay [2]

Answer:

R₁ = 0.126 m

Explanation:

Let's use the definition of intensity which is the power per unit area

          I = P / A

the generated power is constant

          P = I A

power is

         P = E / t

if we perform the calculations for a given time, the wave energy is

        E = q V

we substitute

        P = \frac{q V\ A}{t}

we can write this equation for two points, point 1 the antenna and point 2 the receiver

         V₁A₁ = V₂A₂

          A₁ = \frac{V_2}{V_1} \ A_2

          A₁ = 0.1 10⁻³  5 10⁻⁴ /V₁

          A₁ = 5 10⁻⁸ /V₁

In general, the electric field on the antenna is very small on the order of micro volts, suppose V₁ = 1 10⁻⁶ V

           

let's calculate

          A₁ = 5 10⁻⁸ / 1 10⁻⁶

         A₁ = 5 10⁻² m²

the area of ​​a circle is

          A = π r²

we substitute

         π R1₁²= 5 10⁻²

         R₁ = \sqrt{    \frac{5 \ 10^{-2} }{\pi } }}

         R₁ = 0.126 m

5 0
3 years ago
until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track , it can speed up to
kiruha [24]

Answer:

5

Explanation:

6 0
3 years ago
Compare and contrast the energy transfer of a roller coaster to that of a pendulum
Softa [21]

When the pendulum and roller coaster move to the top, its has more potential energy whereas when comes to the bottom has more kinetic energy.

<h3>Compare and contrast the energy transfer of a roller coaster to that of a pendulum:</h3><h3>What is the transfer of energy in a roller coaster?</h3>

The transfer of potential energy to kinetic energy occur when the roller coaster move along the track. As the motor pulls the cars to the top, the body has more potential energy whereas when the body comes to the bottom , it has kinetic energy in the object.

<h3>What is the energy transfer in a pendulum?</h3>

As a pendulum swings, its potential energy changes to kinetic energy and kinetic energy changes into potential energy. At the top more potential energy is present.

So we can conclude that When the pendulum and roller coaster move to the top, its has more potential energy whereas when comes to the bottom has more kinetic energy.

Learn more about energy here: brainly.com/question/13881533

#SPJ1

8 0
2 years ago
The magnitude, M, of an earthquake is represented by the equation M=23logEE0 where E is the amount of energy released by the ear
vfiekz [6]

Answer:

The amount of energy released by the earthquake in joules is 4.4×10^12 J.

Explanation:

As, we have given the magnitude,

M = 2/3 Log E/Eo

where E is the amount of energy released by the earthquake in joules and Eo=10^4.4 is the assigned minimal measure released by an earthquake.

As, the magnitude is given which is 5.5 then put it in the above equation,

5.5 = 2/3 Log E/Eo

Log E/Eo = 5.5×3 / 2

Log E/Eo = 8.25

Now, we will find the amount of energy released by an earthquake:

Log E/Eo = 8.25

Taking antilog,

E/Eo = 10^8.25

But Eo is given which is Eo = 10^4.4

E/(10^4.4) = 10^8.25

E = 10^8.25 × 10^4.4

E = 4.4×10^12 J.

8 0
4 years ago
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