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Brums [2.3K]
3 years ago
13

Einstein and Lorentz, being avid tennis players, play a fast-paced game on a court where they stand 20.0 m from each other. Bein

g very skilled players, they play without a net. The tennis ball has mass 0.0580 kg. You can ignore gravity and assume that the ball travels parallel to the ground as it travels between the two players. Unless otherwise specified, all measurements are made by the two men. (a) Lorentz serves the ball at 80.0 m>s. What is the ball’s kinetic energy? (b) Einstein slams a return at 1.80 * 108 m>s. What is the ball’s kinetic energy? (c) During Einstein’s return of the ball in part (a), a white rabbit runs beside the court in the direction from Einstein to Lorentz. The rabbit has a speed of 2.20 * 108 m>s relative to the two men. What is the speed of the rabbit relative to the ball? (d) What does the rabbit measure as the distance from Einstein to Lorentz? (e) How much time does it take for the rabbit to run 20.0 m, according to the players? (f) The white rabbit carries a pocket watch. He uses this watch to measure the time (as he sees it) for the distance from Einstein to Lorentz to pass by under him. What time does he measure?

Physics
1 answer:
igor_vitrenko [27]3 years ago
3 0

Answer:

A) 185.6 J

B) 9.396 x 10^14 J

C) 4x10^7 m/s

D) 20 m

E) 9.09x10^-8 sec

F) 9.09x10^-8 sec

Explanation:

Detailed explanation and calculation is shown in the image below

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A ball of mass 4.5 kg moving with speed of 2.2 m/s in the +x-direction hits a wall and bounces back with the same speed in the x
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Answer:

The change of the momentum of the ball is -19.8\, \frac{mkg}{s}

Explanation:

We should find \varDelta\overrightarrow{p}=\overrightarrow{p_{f}}-\overrightarrow{p_{i}} (1)with \overrightarrow{p_{i}} the initial momentum and \overrightarrow{p_{f}} the final momentum. Linear momentum is defined as \overrightarrow{p}=m\overrightarrow{v}, using that on (1):

\varDelta\overrightarrow{p}=m \overrightarrow{v_{f}}-m \overrightarrow{v_{i}} (2)

It's important to note that momentum and velocity are vectors and direction matters, so if +x direction is the direction towards the wall and the -x direction away the wall \overrightarrow{v_{i}}=+2.2\, \frac{m}{s} and \overrightarrow{v_{f}}=-2.2\, \frac{m}{s} so (2) becomes:

\varDelta\overrightarrow{p}=m(-2.2- (+2.2))=-(4.5)(4.4)

\varDelta\overrightarrow{p}=-19.8\, \frac{mkg}{s}

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3 years ago
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How many non-square numbers lie between the squares of 12 and 13?

Answer

VerifiedVerified

96.3k+ views

12.3k+ likes

Hint: Here, we can see that 12 and 13 are consecutive numbers. So, all numbers between squares of 12 and 13 are non-square numbers. Therefore, first find squares of 12 and 13 and then subtract square of 12 from square of 13, we get numbers of non-square numbers. At the last subtract 1 from the result obtained as both extremes numbers are not included.

Complete step-by-step answer:

In these types of questions, a simple concept of numbers should be known that is between squares of two consecutive numbers all numbers are non-square numbers. Also one tricky point should remember that whenever we find the difference between two numbers we get a number of numbers between them including anyone of the extreme numbers. So we subtract 1 to exclude both extreme numbers.

Square of 12 = 122=144 and square of 12 = 132=169

As 12 and 13 are consecutive numbers so all numbers between their squares will be non-square numbers.

Therefore, 169 – 144 = 25

Total number of numbers between 169 and 144 (i.e., excluding 144 and 169) = 25 – 1 = 24.

Explanation:

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I hope this helps!!!
</span>
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