A steady-state plasma concentration of 25 mg/L v by IV infusion to healthy volunteers (average weight, 75 kg) at a rate of 7.5 m

Question

3 years ago

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A steady-state plasma concentration of 25 mg/L v by IV infusion to healthy volunteers (average weight, 75 kg) at a rate of 7.5 m

g/kg/hr for 6 hours. Calculate the total body clearance of this drug. A. 12.5 L/hr B. 22.5 L/hr C. 42.5 L/hr D. 62.5 L/hr was measured when a drug was given

Chemistry

1 answer:

Aleks [24] · Answer 1 · 2022-09-24T21:45:20+03:00

Answer:

The correct answer is option B.

Explanation:

Concentration of a steady-state plasma ,= 25 mg/L

Weight of the volunteer =75 kg

Rate of infusion = 7.5 mg/kg hr

Concentration of steady-state plasma in 75 kg weight body:

$7.5 mg/kg hr\times 75 kg=562.5 mg/hr$

Total body clearance of this drug:

$\frac{562.5 mg/hr}{25 mg/L}=22.5 L/hr$

The total body clearance of this drug is 22.5 L/hr.