Displacement is simply the change in position, or the difference in the final and initial positions:
Then
(a) ∆<em>d</em> = 5 m - 0 m = 5 m
(b) ∆<em>d</em> = 1 m - (-2 m) = 1 m + 2 m = 3 m
(c) ∆<em>d</em> = 2 m - (-2 m) = 2 m + 2 m = 4 m
(d) ∆<em>d</em> = 6 m - 2 m = 4 m
If the net force on object A is 5 N and the net force on object B is 10 N, then object B will accelerate more quickly than object A provided the mass of both objects are same.
Answer: Option C
<u>Explanation: </u>
According to Newton’s second law of motion, any external force applied on an object is directly proportional to the mass and acceleration of the object. In order to state this law in terms of acceleration, it is stated that acceleration exhibited by any object is directly proportional to the net force applied on the object and inversely proportional to the mass of the object as shown below:
So if two objects A and B are identical which means they have same mass, then the acceleration attained by the object will be directly proportionate to the net forces exerted on the objects only.
Thus if the force applied is more for one object, then the object will be exhibiting more acceleration compared to the other one. So as object B is experiencing a net force of 10 N which is greater than the net force experiences by object A, then the object B will be accelerating more quickly compared to the object A's acceleration.
Answer:
<em>1.49 x </em><em></em>
<em></em>
Explanation:
Kepler's third law states that <em>The square of the orbital period of a planet is directly proportional to the cube of its orbit.</em>
Mathematically, this can be stated as
∝
<em>to remove the proportionality sign we introduce a constant</em>
= k
k =
Where T is the orbital period,
and R is the orbit around the sun.
For mars,
T = 687 days
R = 2.279 x
for mars, constant k will be
k = = 3.987 x
For Earth, orbital period T is 365 days, therefore
= 3.987 x
x
= 3.34 x
R =<em> 1.49 x </em><em></em>